# Parallel Forces Physics Lab

Objective: Find FA and FB on the apparatus which are parallel to both Fulcrum A and B.

Calculations:

Theoretical FB

Στ = 0

+FB 0.5 - (0.1kg x g x 0.1m) - (0.2kg x g x 0.4m) - (0.05kg x g x 0.7m) - (0.1kg x g x 0.3m) = 0 -[{(0.1kg x 0.1m) + (0.2kg x 0.4m) + (0.05kg x 0.7m) + (0.1kg x 0.3m)}x 9.8] + 0.5FB = 0 0.5FB = [(0.1 x 0.1) + (0.2 x 0.4) + (0.05 x 0.7) + (0.1 x 0.3)]x 9.8 FB =

FB = 3.04 N

Experimental FB

FB = mpanB g - mfulcrumB g

FB = (0.385kg x 9.8) - (.0816kg x 9.8) = 3.77 - .800

FB = 2.97 N

Theoretical FA

-[(0.1kg x g) + (0.2kg x g) + (0.05kg x g) + (0.1kg x g)] + FA + FB = 0 -[(0.1kg x g) + (0.2kg x g) + (0.05kg x g) + (0.1kg x g)] + FA + 3.04N = 0 -4.41 + FA + 3.04 = 0

FA - 1.37 = 0

FA = 1.37 N

Experimental FA

FA = (mpanA x g) - (mfulcrumA x g)

FA = (0.205kg x 9.8) - (.0693kg x 9.8) = 2.01 - .679

FA = 1.33 N

Conclusion:

Since the distance of FB is greater than that of FA, the torque of FB is larger. The line of FA, lies directing on the 0.2 m axis, causing a torque of zero for FA. The theoretical and experimental values for both forces are very close, supporting the theory of torque and parallel forces.

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