Children’s Functional Health Pattern Assessment
Functional Health Pattern Assessment (FHP)| ToddlerErickson’s Developmental Stage:| Preschool-AgedErickson’s Developmental Stage:| School-AgedErickson’s Developmental Stage:| Pattern of Health Perception and Health Management:List two normal assessment findings that would be characteristic for each age group. List two potential problems that a nurse may discover in an assessment of each age group.| | | | | | | |

Nutritional-Metabolic Pattern:List two normal assessment findings that would be characteristic for each age group. List two potential problems that a nurse may discover in an assessment of each age group.| | | | | | | |

Pattern of Elimination:List two normal assessment findings that would be characteristic for each age group. List two potential problems that a nurse may discover in an assessment of each age group.| | | | | | | |

Pattern of Activity and Exercise:List two normal assessment findings that would be characteristic for each age group. List two potential problems that a nurse may discover in an assessment of each age group.| | | | | | | |

Cognitive/Perceptual Pattern:List two normal assessment findings that would be characteristic for each age group. List two potential problems that a nurse may discover in an assessment of each age group.| | | | | | | |

Pattern of Sleep and Rest:List two normal assessment findings that would be characteristic for each age group. List two potential problems that a nurse may discover in an assessment of each age group.| | | | | | | |

Pattern of Self-Perception and Self-Concept:List two normal assessment findings...

...illiterate in my life. One way that I think has had the biggest impact in my life was not having the “normal” family that most kids seem to have growing up. I never had the family where the mom bakes all the time and takes her kids to soccer practice and drives a mini van, while the dad doesn’t come home until later at night just to help his kids with their homework and tells them goodnight while him and his wife talk about their day apart. Instead, I was the girl that had the parents that always fought about my mother’s drinking problem and how she was single-handedly ruining our family while my father owned his own business and did not come home until late at night just to find my mother had left me home alone to go the bar. After that, I was that girl that had the divorced parents. Not only did I have the divorced parents, but also I was that girl that was the odd one out that lived with her father and not her mother. I was so embarrassed about my family life because I thought that I was literally the only person that had that family situation, I never thought that anyone else could have the same family problems as me, or that it was more common than what I had thought.
After a couple years of living with my dad and rarely seeing my mom because of the things that she had done, I became that girl with the stepmother and new family that on the outside looked like the “normal” family that I had always wanted. For a while it was everything...

...Children’s Functional Health Pattern Assessment
Functional Health Pattern Assessment (FHP)
Toddler
Erickson’s Developmental Stage:
Preschool-Aged
Erickson’s Developmental Stage:
School-Aged
Erickson’s Developmental Stage:
Pattern of Health Perception and Health Management:
List two normalassessmentfindings that would be characteristic for each age group.
List two potential problems that a nurse may discover in an assessment of each age group.
Autonomy versus shame and doubt
Normal: Toddlers looking to parents for guidance and instruction for personal hygiene as well as the food choices they have. Initiative versus guilt
Normal: Preschool-aged children should be given small chores around the house to contribute to the household as well as a schedule to do personal hygiene. Industry versus inferiority
Normal: Child is aware that coughing and sneezing spreads germs and that washing hands and taking pride in personal hygiene can reduce incidences of being ill.
Potential Problems: If chosen diet by the parents is not a healthy one it can lead to child being undernourished and having poor dietary choices, also toddlers may not be open to try new food choices. Potential Problems: A child not aware of the need for hygiene or not compliant with the regimen as well as children that are not compliant with the...

...Low-cost airlines like Easyjet, have picked up some customers from their traditional competitors like BA (British Airways) or Air France, but have specially created a large traffic of induction (creating a new market). Easyjet operates in a different way to Ryan Air - its direct competitor in the market, which is targeting the leisure traveller for whom the ticket price is important. Easyjet has the same type of clientele for whom the ticket price was slightly less important and also business customers whose companies seek to save on transportation costs, but care about the travel’s conditions. So Easyjet has two different kind of customers who are leisure customers and the business customers.
1.2 Easyjet’s marketing mix
Product
Easyjet is a business offering service products, flights across destinations, in the transportation industry. Easyjet operates over 500 routes and has 182 aircrafts in 28 countries (www.easyjet.com).
Easy-Jet positions itself as low-cost airlines or better as cutting costs airlines. Its product strategy stops to the actual product without concern about the augmented product. They don't offer service at all but just the ticket. For example Easy-Jet's product strategy ends at the expected level of five-product levels. There is no augmented product. There is no business seat on flights (Easyjet offer a mono class of seat but does not offer last minute deals), no executive lounge at airports, no free food and drinks on flights, no entertainment...

...
What is normal? Normal, like the word love, has no true definition and will differ with every person you ask. Defined in the dictionary normal is “to conform to a particular standard” or “desired pattern”. I believe most people will say a normal person is one whom is free from defect, handicap and mental illness. Medicalization is a social process through which a previously normal human condition whether is be behavioral, physiological or emotional, becomes a medical problem in need of treatment. For example, not long ago being a shy person, “being reserved or having or showing nervousness or timidity in the company of other people”, was common and something most people experienced at some points in their lives. However, now shyness is out the realm of normal and made it’s way into medical books. A shy person may now be one who is suffering from “avoidant personality disorder” or a number of other anxiety-relation mental disorders that has to be treated with antidepressants. In Saving Normal, Dr. Allen Frances argues that a high percentage of people diagnosed with mental illness are actually normal. This widespreasd medicalization of normality is leading to over-treatment and over-medicating of mental health issues. The biggest health threat that we face may be our health-care system.
The Diagnostic and Statitical Manual of Mental Disorders, DSM, has...

...area under a Standard Normal curve
a) to the right of z is 0.3632;
b) to the left of z is 0.1131;
c) between 0 and z, with z > 0, is 0.4838;
d) between -z and z, with z > 0, is 0.9500.
Ans : a) z = + 0.35 ( find 0.5- 0.3632 = 0.1368 in the normal table)
b) z = -1.21 ( find 0.5 – 0.1131 = 0.3869 in the normal table)
c ) the area between 0 to z is 0.4838, z = 2.14
d) the area to the right of +z = ( 1-0.95)/2 = 0.025, therefore z = 1.96
3. Given the Normally distributed variable X with mean 18 and standard deviation 2.5, find
a) P(X < 15);
b) the value of k such that P(X < k) = 0.2236;
c) the value of k such that P(X > k) = 0.1814;
d) P( 17 < X < 21).
Ans : X ~ N ( 18, 2.52)
a) P ( X < 15)
P ( Z < (15-18)/2.5) = P ( Z < -1.2) = 0.1151 ( 4 decimal places)
b) P ( X < k) = 0.2236
P ( Z < ( k – 18) / 2.5 ) = 0.2236
From normal table, 0.2236 = -0.76
(k-18)/2.5 = - 0.76, solve k = 16.1
c) P (X > k) = 0.1814
P ( Z > (k-18)/2.5 ) = 0.1814
From normal table, 0.1814 = 0.91
(k-18)/ 2.5 = 0.91, solve k = 20.275
d) P ( 17 < X < 21)
P ( (17 -18)/2.5 < Z < ( 21-18)/2.5)
P ( -0.4 < Z < 1.2) = 0.8849 – 0.3446 = 0.5403 ( 4 decimal places)...

...exactly 3 will go through in a given minute using the correct table, formula, or Excel function. Solution: Poisson with average of 7. want P(3). P(3) = .052 18. How do you recognize a normal distribution? Solution: It is symmetric about the mean and has a bell-shape to it. 19. Label a) b) c) d) the following as continuous or discrete distributions. The lengths of fish in a certain lake. The number of fish in a certain lake. The diameter of 15 trees in a forest. How many trees are on a farmer's acre.
Solution: (a) continuous; (b) discrete; (c) continuous; (d) discrete 20. Jack weighs 160 pounds and his sister weighs 110 pounds. If the mean weight for men his age is 175 with a standard deviation of 14 pounds and the mean weight for women is 145 with a standard deviation of 10 pounds, determine whose weight is closer to "average." Write your answer in terms of z-scores and areas under the normal curve. Solution: for Jack z = 1.07, area = .1423 for his sister = .0062
x−µ =
x−µ
σ
=
160 − 175 − 15 = ≈ −1.07 , when z = 14 14
σ
110 − 145 − 25 = = −2.50 , when z = -2.50, area 10 10
Jack is closer to average, but he is still in the lower 14%, while his sister is in the bottom less than 1% of the population.
21. On a dry surface, the braking distance (in meters) of a certain car is a normal distribution with mu = µ = 45.1 m and sigma = σ = 0.5 (a) Find the braking distance that corresponds to z = 1.8 (b) Find the...

...NORMAL DISTRIBUTION
1. Find the
distribution:
a.
b.
c.
d.
e.
f.
following probabilities, the random variable Z has standard normal
P (0< Z < 1.43)
P (0.11 < Z < 1.98)
P (-0.39 < Z < 1.22)
P (Z < 0.92)
P (Z > -1.78)
P (Z < -2.08)
2. Determine the areas under the standard normal curve between –z and +z:
♦ z = 0.5
♦ z = 2.0
Find the two values of z in standard normal distribution so that:
P(-z < Z < +z) = 0.84
3. At a university, the average height of 500 students of a course is 1.70 m; the standard
deviation is 0.05 m. Find the probability that the height of a randomly selected student is:
1. Below 1.75 m
2. Between 1.68 m and 1.78 m
3. Above 1.60 m
4. Below 1.65m
5. Above 1.8 m
4. Suppose that IQ index follows the normal distribution with µ = 100 and the standard
deviation σ = 16. Miss. Chi has the IQ index of 120. Find the percentage of people who
have the IQ index below that of Miss. Chi.
5. The length of steel beams made by the Smokers City Steel Company is normally
distributed with µ = 25.1 feet and σ = 0.25 feet.
a. What is the probability that a steel beam will be less than 24.8 feet long?
b. What is the probability that a steel beam will be more than 25.25 feet
long?
c. What is the probability that a steel beam will be between 24.9 and 25.7
feet long?
d. What is the probability that a steel beam will be between 24.6 and 24.9
feet long?
e. For a particular application, any beam less than 25 feet...

...thrown downwards from a tall building at 5m/s. which statement is true after it is released?
*
A crate (80 kg) is hung in an elevator by a cord rated to withstand a tension of 1200 N. The elevator starts at rest and begins moving upwards until the cord holding the crate breaks. What was the acceleration of the elevator when the cord broke? Assume g = 10 m/s2
Top of Form
(T1R + W1E)/ mass |
Bottom of Form
Block 1 (4 kg) is located on the surface of a table. A hand pushes horizontally to the right on block 1 with a normal force of 16 N.
On a sheet of paper, draw the free body diagram for block 1 using the two-subscript notation from class. After completing the free body diagram, enter below each force and its x & y-components. Remember that the x-component is the "i" component and the y-component is the "j" component.
FORCES on BLOCK 1
Weight force on block 1 by Earth
W1E = 0 i + -40 j N
Normal force on block 1 by Surface
N1S = 0 i + 40 j N
Normal force on block 1 by Hand
N1H = 16 i + 0 j N
| You are correct. Computer's answer now shown above.
Your receipt no. is 161-8237 | Previous Tries |
What is the acceleration a of block 1?
a = 4 i + 0 j m/s2
Block 1 (m1 = 6 kg) and block 2 (m2 = 16 kg) are adjacent to each other on the surface of a table. Block 2 is to the LEFT of block 1. A rope pulls at an angle on block 2 to the right with a vertical tension component of 110 N upward, and both blocks move right with...

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