Mole Relationship in a Chemical Equation

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To react NaHCO3 with HCl to form NaCl and two other products and then calculate the mole relationships between NaHCO3 and NaCl and calculate a balanced equation for this reaction.

Wear safety goggles at all time
Handle all chemicals with care
Use equipment like tongs when handling warm/hot objects
If chemicals are spilt on self, wash off immediately
Stand at all times

The NaHCO3 will react successfully with the HCl and will form NaCl, H2O and CO2. Then be able to work out a balanced equation for the reaction and work out the moles of NaHCO3 and NaCl.

Evaporating basin
Watch glass
Dropping pipette
250ml beaker
50ml beaker
10ml measuring cylinder
Bunsen burner
Gauze mat
Rubber mat
Beaker tongs
Distilled water bottle
6 molar/litre HCl

1.Measured the weight of the empty evaporating basin to the nearest 0.01grams. 2.With the spatula, added exactly 1.5g to the evaporating basin and then wrote down the weight of the basin and the NaHCO3. 3.Measured out 6ml of the 6 molar HCl into the 10ml measuring cylinder and then transferred that into the 50ml beaker. 4.Placed watch glass over the evaporating basin and slowly added the HCl by using the pipette. Dropped the HCl in by allowing it to enter via the lip of the evaporating basin and letting the HCl slide slowly in. 5.Continued adding the HCl to the NaHCO3 until no more reaction occurred. Double checked by swirling the basin around to see if the HCl had reached all of the NaHCO3. 6.Then removed watch glass from basin with tongs and let the liquid fall into the evaporating basin. What was left on the watch glass was rinsed with a very minimal amount of distilled water into the basin. 7.Filled the 250ml beaker with a 1/3 of water and prepared the Bunsen burner. Then placed the evaporating basin over the beaker and placed the beaker over the Bunsen burner hence creating a water bath. Continued to heat liquid until it dried into a solid taking care not to let it over boil. 8.Once all moisture evaporated, removed basin from beaker and allowed to cool. Once cool enough to touch weighed the mass of the substance and basin to the nearest 0.01grams. 9.After weighing mass, rinsed substance down the drain and cleaned up.


Basin + NaHCO330.50g
Basin + NaCl30.41g


Moles of NaHCO3= given weight
Molecular weight
approximately =0.018

Moles of NaCl = given weight
Molecular weight
= 0.024102564
approximately = 0.024

3) Ratio

NaHCO3 : NaCl
0.018 : 0.24
0.018 / 0.018 : 0.024 /0.018
1 : 1.333
1 x 3 : 1.333x 3
3 : 4

Balanced chemical equation=

NaHCO3 + HCl NaCl + H2O + CO2

In our experiment we reacted HCl with NaHCO3 which formed NaCl, water and CO2. During the experiment noticed that adding the HCl to the NaHCO3, it fizzed with quite audible sounds and continued to do so until every particle was dissolved. It also made the watch glass foggy due to the water vapor produced by the reaction. We know that our balanced equation is correct through the law of conservation of mass which states that matter can be neither created nor destroyed but can change forms. From our results we know that we had 1.5g of NaHCO3 (the mass of the basin and the NaHCO3 minus the basin) and once we added the HCl to create the NaCl, the NaCl weighed to be 1.41g. So it weighed to be...
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