The Internal-External (IE) Matrix
The Internal-External (IE) Matrix positions an organization's various divisions in a nine cell display illustrated in Figure 6-9. The IE Matrix is similar to the BCG Matrix in that both tools involve plotting organization divisions in a schematic diagram; this is why

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FIGURE 6-9
The Internal-External (IE) Matrix
THE IFE TOTAL WEIGHTED SCORES StrongAverageWeak
3.0 to 4.02.0 to 2.991.0 to 1.99 Grow and build4.03.02.0t n
[pic]
THE
EFE
Medium
TOTAL 2.0 to 2.99
WEIGHTED
SCORES
Low
1.0 to 1.99
High
3.0-4.-0

Hold and maintainHarvest or divest
Note: The IE Matrix was developed from the General Electric (GE) Business Screen Matrix. For a description of the GE Matrix, see Michael Allen, "Diagramming GE's Planning for What's WATT" in Corporate Planning: Techniques and Applications, eds. R. Allio and M. Pennington (New York: AMACOM, 1979)

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they are both called portfolio matrices. Also, the size of each circle represents the percentage sales contribution of each division, and pie slices reveal the percentage profit contribution of each division in both the BCG and IE Matrix. But there are some important differences between the BCG Matrix and IE Matrix. First, the axes are different. Also, the IF Matrix requires more information about the divisions than the BCG Matrix. Further, the strategic implications of each matrix are different. For these reasons, strategists in multidivisional firms often develop both the BCG Matrix and the IE Matrix in formulating alternative strategies. A common practice is to develop a BCG Matrix and an IE Matrix for the present and then develop projected...

...CXC CSEC Physics | Paper 02 | 2001
1. You are to spend no more than ½ hour on this question. In this question you will find the value of the resistance, R, of a heating element. The voltage, V, across the heating element is varied and the power, P, which is dissipated, is measured. (Note that R remains constant during the heating.) A graph of P against V is plotted on page 2. (a) Select 6 pairs of values of P and V from the graph and insert these along with corresponding values of V2 in Table 1 below. P (watts) V (volts) V2 (volts 2) Table 1 (b) (c) Plot a graph of P against V2 on the graph sheet. Find the slope, S, of the graph you have plotted. ……………………………………………………………………………………………… ……………………………………………………………………………………………… (4 marks) (d) The equation for the beating element is Use this equation and your value for R so as to find the resistance of the heating element. ……………………………………………………………………………………………… ……………………………………………………………………………………………… ……………………………………………………………………………………………… (3 marks) (e) Estimate the power, P,, which would be dissipated in the element if the applied voltage is 300 volts. ……………………………………………………………………………………………… ……………………………………………………………………………………………… (3 marks) (f) If 300 V were applied for 15 minutes, calculate the energy used in kWh. ……………………………………………………………………………………………… ……………………………………………………………………………………………… (3 marks) Total 30 marks
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(8 marks)
(9 marks)
CXC CSEC Physics | Paper 02 | 2001
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