# Math 208 Week One Individual

Write the interval of real numbers in interval notation and

graph it. See Example 5.

50. The set of real numbers less than or equal to -4

Consider the following nine integers:

-4, -3, -2, -1, 0, 1, 2, 3, 4

94. Which of these integers has an absolute value greater

than 1?

Solution:

-4, -3, -2, 2, 3, 4

Write the interval notation for the interval of real numbers shown in the graph.

__________________

-50 -40 -30 -20 -10 0

A B

Hint: replace a with (-3) and evaluate each expression. Which are positive and which negative?

(a)-3 solution: positive

(b)|-3| solution: positive

(c)-|3| solution: negative

(d)-(-3) = 3 solution: negative

(e)-|-3| solution: negative

Chapter 1 - Section 1.2

Build up the fraction so that it is equivalent

to the fraction with the indicated denominator. See Example 1.

5/7=?/98 (fraction problem)

Let the missing number be x then

Therefore,

Convert the given fraction to both decimal and percent. See Example 8 or use a calculator.

19/20 = 0.95, 95%

Perform the indicated operations. See Example 7c.

Chapter 1 - Section 1.3

Fill the correct value in the parentheses to make the statement correct. See Example 4.

Solution :

-9-(-2.3) = -9 + 2.3

Perform the indicated operations.

-19-13=-32

Perform the indicated operations.

15 + (-39) = 15 – 39 = -24

Fill in the correct value in the parentheses so the equation is correct.

Let the missing number be x then

13 + x = -4

Subtract 13 from each side, we will get

x = -4 – 13 = -17

13 + (-17) = -4

Answer: -17

Chapter 1 - Section 1.4

Perform the indicated operation.

(-8)(-6) = 48

Perform the indicated operations and reduce to lowest terms.

-9/10 x4/3

Solution:

= - 36/30 = -6/5

Fill in the correct value in the parentheses so the equation is correct.

-48 divided by ( )=6

-48/ x = 6

-48 = 6x

x = -48/6 = -8

Therefore, -48 (-8) = 6

Chapter 1 - Section 1.5

Evaluate the expression using order of operations.. See Example 8.

3[(2-3)^2 +6(6-4)^2]

= 3[(-1)^2 + 6*(2)^2]

= 3[1 + 24] = 3*25 = 75

Evaluate each expression using order of operations.. See Example 8 a)

8 – 3 |5 - 4 + 1 |

= 8 – 3|5-16+ 1|

= 8 – 3|-10| = 8-3*10 = 8 – 30 = -22

Chapter 1 - Section 1.6

Evaluate each expression using a = -1, b = 2, and c = -3.

See Example 4.

(a – c)(a + c) = a^2 – c^2 = (-1)^2 – (-3)^2 = 1 – 9 = -8

Determine whether the given number is a solution to the

equation following it. See Example 5.

Let us substitute x = 5 in the given equation, we will get

3(5) + 7 = 2(5) – 1

15 + 7 = 9

22 = 9

Which is not true

Therefore 5 is not the solution of the given equation

Chapter 1 - Section 1.7

Use the commutative and associative properties of multiplication and exponential notation to rewrite each product. See

Example 3.

y(y*5)(wy)

y(y * 5)(wy) =5wy3

Use the distributive property to remove the parentheses.

See Example 5.

-3(6-p)

3 (6 – p) = (-3)6 –(-3)p = -18 + 3p

Chapter 1 - Section 1.8

Combine like terms where possible. See Example 3.

Simplify the following expression by combining like terms.

See Example 8.

2a(a - 5) + 4(a -5)

= 2a2 – 10a + 4a – 20

= 2a2 – 10a + 4a – 20

= 2a2 – 6a – 20

Simplify the expression.

1/4(6b+2)-2/3(3b-2) (Please note!! the ¼ and the 2/3 are fractions)

Solution:

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