Solving a proportion as we learned this week, means that you are missing an import number in your equation or fraction, and you need to solve for that missing value. As in my example, I did not know what percentage of bills we each should pay. We knew each other’s salaries; but we really had to sit down, crunch numbers, and figure it out. For this week’s assignment we were asked to work through two proportions. For the first proportion, number 56 on page 437 of Elementary and Intermediate Algebra by Dugopolski: estimate the size of the bear population on the Keweenaw Peninsula, conservationists captured, tagged, and released 50 bears. One year later, a random sample of 100 bears included only 2 tagged bears. What is the conservationist’s estimate of the size of the bear population? Beginning to solve this equation first, we needed to make a proportion with the number of tagged bears in the sample and in the population:

Number of the tagged bears in the sample compared to the sample size equals the number of tagged bears in the population: Population size. The population size is “x”, we need to solve for “x” as such: 2/100 = 50/x

Cross multiply or use the extremes means property
2 * x = 100 * 50
2x = 5000
Because we want to solve for “x” we must isolate it by dividing both sides by two. x = 5000/2 = 2500
Answer: x= 2500 bears
For the second problem, number 10 on page 444: we must solve the equation for y: Y-1 = - 3
X+3 4

Cross multiplying or use the extremes means property. According to Dugopolski, “We use the extremes-means property to solve proportions” (Dugopolski, 2011).

4*(y-1) = -3*(x+3)

[Distribute by 4 on the left and -3 on the right.

4y - 4 = -3x - 9

Add 4 to both sides and reduce to lowest terms.

4y - 4 + 4 = - 3x - 9 + 4
4y = -3x – 5

Divide each side by 4
y = (-3/4)x - (5/4) or y= -3x-5
4

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Ashford MAT222WEEK1 TO 5
Week1, Assignment, Solving Proportions
Read the following instructions in order to complete this assignment:
1. Solve problem 56 on page 437 of Elementary and Intermediate Algebra. Set up the two ratios and write your equation choosing an appropriate variable for the bear population.
2. Complete problem 10 on page 444 of Elementary and Intermediate Algebra. Show all steps in solving the problem and explain what you are doing as you go along.
3. Write a two to three page paper that is formatted in APA style and according to the Math Writing Guide. Format your math work as shown in the example and be concise in your reasoning. In the body of your essay, please make sure to include:
Your solution to the above problems, making sure to include all mathematical work, and an explanation for each step
A discussion of the following: What form of an equation do you end up with in problem 10? What do you notice about the coefficient of x compared to the original problem? Do you think there might be another way to solve this equation for y than with the proportion method? How would you do it?
An incorporation of the following four math vocabulary words into your paper. Use bold font to emphasize the words in your writing. (Do not write definitions for the words; use them appropriately in...

...REAL WORLD RADICAL FORMULAS
Krissel Aromin
MAT222 Week 3 Assignment
5/20/2014
Introduction
In this paper I will be discussing on radical formulas and how to solve for the formula that is given as C = 4d^-1/3b where d is the displacement in pounds and b is the beam width in feet. The exponent of -1/3 means that the cube root of d will be taken and then the reciprocal of the number will be used in the multiplication. These rules include accurately finding the cube and square root for numbers and understanding the application of the solution in sailboat stability (Example, 2013).
Sailboat Stability
In this paper we will need to solve problem #103 on page 605 Sailboat Stability (Dugopolski, 2012). In order to consider safe for ocean sailing the capsize screening value C should be less than 2. For a boat with a beam (width) b in feet and displacement d in pounds, C is determined by the function C=4d-1/3b (Dugopolski, 2012). In the beginning of the problem radicals look difficult at first, but the idea ranges through exponents and order of operations. To start out the problem we have to solve a, b, and c.
a) Find the capsize screening value for the Tartan 4100, which has a displacement of 23,245 pounds and a beam of 13.5.
C=4d-1/3b
C= 4(23245)-1/3(13.5) I have plugged in the values into the formula. Allowing the order of operations, the...

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Solving Proportions
Jubenal Garcia
MAT222: Intermediate Algebra (GSQ1433A)
Instructor Linda Seeger
August 19, 2014
Solving Proportions
This week I learned about solving proportions. Rightfully so, on this assignment I have to prove or show what I’ve learned and retained by solving two problems. In this essay I will attempt to solve two problems from our textbook, the first one is problem 56 located on page 437 and the second one is problem 10 located on page 444 of our Elementary and Intermediate Algebra textbook. During this process I will incorporate the four math vocabulary words required, which are extraneous, proportion, cross multiply, and extreme-means which will be in bold.
Problem number 56 located on page 437 states and asks the following about bear population. “To estimate the size of the bear population on the Keweenaw Peninsula, conservationist captured, tagged, and released 50 bears. One year later, random sample of 100 bears included only 2 tagged bears. What is the conservationist’s estimate of the size of the bear population?” (Dogupolski, 2012). Since this is a ratio equation I will use b for the variable, b equaling the bear population which is what we need to find.
The first thing I did was to set up the two ratios, place the b for the variable which equals the bear population in this proportion. Then I cross multiply the extreme-means property as shown below.
2*b=100*50
2b=5000
Because...

...Wright
MAT222Week 2 Assignment
Instructor: Dr. Stacie Williams
December 14, 2013
In Elementary Algebra we have learned how to solve systems of equations. The solution to a system of linear equations is the point where the graphs of the lines intersect. The solution to a system of linear inequalities is every point in a region of the graph where the inequalities overlap, rather than the point of intersection of the lines (Slavin, 2001).
This weekassignment required to solve problem 68 on page 539 (Dugopolski, 2012). I will be giving a detailed presentation on math required for the solution to this problem; the accompanying graph shows all of the possibilities for the number of refrigerators and the number of TVs that will fit into an 18-wheeler. The point-slope form of a linear equation to write the equation itself can now be used. These are the steps we take to solve our linear inequality. I will start with the point-slope form. Substitute slope form with (300, 0) for the x and y. Next we are going to use the distributive property and then add 330 to both sides and divided both sides by -3 and cancel out like terms.
The graph has a solid line rather than a dashed line indicating that points on the line itself are part of the solution set. This will be true anytime the inequality symbol has the equal to bar.
a) Write an inequality to...

...Solving Proportions
Tara Lint
MAT222Week1Assignment
Instructor: James Segala
August 18, 2013
Solving Proportions
Proportions exist in the real world. For example, in finding out the price of a unit, or the population of a specific species. The first problem that we are working with states that “. Bear population. To estimate the size of the bear population on the Keweenaw Peninsula, conservationists captured, tagged, and released 50 bears. One year later, a random sample of 100 bears included only 2 tagged bears.What is the conservationist’s estimate of the size of the
bear population?(Dugolpolski, 2012)
In reading over the “Bear Population” #56 on page 437 (Dugolpolski, 2012), the concept of proportions allow the assumption that the ratio of originally tagged bears to the whole population is equal to the ratio of recaptured tagged bears to the size of the sample. The estimated solution, variables will be defined and rules for solving proportions are used.
The ratio of originally tagged bears to the whole population is 50/x.
The ratio of recaptured tagged bears to the sample size is 2/100.
50=2 This is the proportion set up and ready to solve. This is the step where we will cross multiply.
x 100 at this point. The extremes are 100 and 50. The means are x and 2
100(50)=2x
50002=2x2 Divide both sides by 2
X=2500 The bear population of Keweenaw Peninsula is estimated to be...

...Real world applications
XXX
MAT126: Survey of Mathematical Methods
Instructor: XXX
May 20, 2012
In this assignment I would like to talk about arithmetic sequences and geometric sequences and want to give an example each how to calculate with those sequences. First I want to give a short definition of each sequence.
“An arithmetic sequence is a sequence of numbers in which each succeeding term differs from the preceding term by the same amount. This amount is known as the common difference.” (Bluman, A. G. 2500, page 221)
An example for an arithmetic sequence is:
1, 3, 5, 7, 9, 11, … (The common difference is 2. (Bluman, A. G. 2500, page 221)
“A geometric sequence is a sequence of terms in which each term after the first term is obtained by multiplying the preceding term by a nonzero number. This number is called the common ratio.” (Bluman, A. G. 2005, p. 225) Here you can see that there is always added 2.
1 + 2 = 3; 3 + 2 = 5; 5 + 2 = 7; 7 + 2 = 9; …
An example for a geometric sequence is:
2, 10, 50, 250, 1250, … (The common ratio is r = 5 (Bluman, A. G. 2005, p. 225)
Here you can see that the 2 is multiplied by 5, which is 10. Then the 10 is also multiplied by 5, which is 50 and so on.
2 x 5 = 10; 10 x 5 = 50; 50 x 5 = 250; 250 x 5 = 1250; …
In this assignment I have solved two exercises, one referring to arithmetic sequences and one referring to geometric sequences....

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Assignment1 – Week1MAT222Assignment1 – Week1
This week’s assignment we are going to solve two word problems. With both of these problems we will be working with proportions that both equal each other. These methods will require cross multiplication and division. After completing that I will find my answer with no variables.
My first equation is as follows: To estimate the size of the bear population on the Keweenaw Peninsula, conservationists captured, tagged, and released 50 bears. One year later, a random sample of 100 bears included only 2 tagged bears. What is the conservationist’s estimate of the size of the bear population?
I would write would write out this proportion as such:
x = 100 x over 50 equals 100 over 2, since I am trying to find out the rough
50 2 guesstimate of the bear population. From here I would cross multiply
the extreme to the mean, 50 by 100 and x by 2.
2x = 5,000 To get x by itself I will now divide 2 on one side and do the same to
the other side.
2x = 5,000
2 2
x = 2,500 My extraneous answer for bear population is 2,500.
My second equation is as follows:
y – 1 = -3 In order to solve for y...

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This paperwork MAT222Week 3 Discussion Questions 1 comprises solutions on the following tasks: Find the rational exponent problems assigned to you in the table below. Simplify each expression using the rules of exponents and examine the steps you are taking. Incorporate the following five math vocabulary words into your discussion. Use bold font to emphasize the words in your writing (Do not write definitions for the words; use them appropriately in sentences describing the thought behind your math work.): - Principal root - Product rule - Quotient rule - Reciprocal - nth root
Mathematics - Algebra
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MAT222MAT/222 MAT222 Algebra
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