Solving a proportion as we learned this week, means that you are missing an import number in your equation or fraction, and you need to solve for that missing value. As in my example, I did not know what percentage of bills we each should pay. We knew each other’s salaries; but we really had to sit down, crunch numbers, and figure it out. For this week’s assignment we were asked to work through two proportions. For the first proportion, number 56 on page 437 of Elementary and Intermediate Algebra by Dugopolski: estimate the size of the bear population on the Keweenaw Peninsula, conservationists captured, tagged, and released 50 bears. One year later, a random sample of 100 bears included only 2 tagged bears. What is the conservationist’s estimate of the size of the bear population? Beginning to solve this equation first, we needed to make a proportion with the number of tagged bears in the sample and in the population:

Number of the tagged bears in the sample compared to the sample size equals the number of tagged bears in the population: Population size. The population size is “x”, we need to solve for “x” as such: 2/100 = 50/x

Cross multiply or use the extremes means property
2 * x = 100 * 50
2x = 5000
Because we want to solve for “x” we must isolate it by dividing both sides by two. x = 5000/2 = 2500
Answer: x= 2500 bears
For the second problem, number 10 on page 444: we must solve the equation for y: Y-1 = - 3
X+3 4

Cross multiplying or use the extremes means property. According to Dugopolski, “We use the extremes-means property to solve proportions” (Dugopolski, 2011).

4*(y-1) = -3*(x+3)

[Distribute by 4 on the left and -3 on the right.

4y - 4 = -3x - 9

Add 4 to both sides and reduce to lowest terms.

4y - 4 + 4 = - 3x - 9 + 4
4y = -3x – 5

Divide each side by 4
y = (-3/4)x - (5/4) or y= -3x-5
4

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Ashford MAT222WEEK1 TO 5
Week1, Assignment, Solving Proportions
Read the following instructions in order to complete this assignment:
1. Solve problem 56 on page 437 of Elementary and Intermediate Algebra. Set up the two ratios and write your equation choosing an appropriate variable for the bear population.
2. Complete problem 10 on...

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This week I learned about solving proportions. Rightfully so, on this assignment I have to prove or show what I’ve learned and retained by solving two problems. In this essay I will attempt to solve two problems from our textbook, the first one is problem 56 located on page 437 and the second one is problem 10...

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Proportions exist in the real world. For example, in finding out the price of a unit, or the population of a specific species. The first problem that we are working with states that “. Bear population. To estimate the size of the bear population on the Keweenaw Peninsula, conservationists captured,...

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In this assignment I would like to talk about arithmetic sequences and geometric sequences and want to give an example each how to calculate with those sequences. First I want to give a short definition of each sequence.
“An arithmetic sequence is a sequence of numbers in which each succeeding term differs from the preceding term by the same amount. This amount is known as the common difference.” (Bluman, A. G. 2500, page 221)
An example for an arithmetic sequence is:...

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******** Long
Assignment1 – Week1MAT222Assignment1 – Week1
This week’s assignment we are going to solve two word problems. With both of these problems we will be working with proportions that both equal each other. These methods will require cross multiplication and division. After completing that I...

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MAT 540 WEEK1 TO 11(Strayer)
MAT540 Week1 Homework
Chapter 1, Problems 2, 4, 12, 14, 20, 22
2. The Retread Tire Company recaps tires. The fixed annual cost of the recapping operation is $60,000.The variable cost of recapping a tire is $9.The company charges $25 to recap a tire.
a. For an annual volume of 12,000 tires, determine the total cost, total revenue, and profit.
b....

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