By: Lashell Marrow
Instr: Shenita Talton
MAT 221: Introduction to Algebra
Date : April 7, 2013

The Body Mass Index (BMI) is an indicator to help people to determine if they might have a longer life span than average, are probably not overweight, are probably overweight, or are obese. The intervals for each are from 17 to 22, 23 to 24.999, 25 to 29.9, and over 30 respectively. Notice that it is between 17 and 22. That is not inclusive but rather a compound inequality statement which is 17 < BMI < 22. Moreover, over 30 is an inequality statement with a positive infinity which is any BMI that is greater than 30, or BMI > 30 which will be written as (30, +∞). Anyway, my BMI will be calculated, and I will explain how I arrived at the results. Sometimes, a person’s BMI can be misleading, so reasons will be provided about why. Finally, there is an evaluation of the regions outside of the “probably not overweight” range by using the set and interval notations along with a simple graph of the regions.

Now, I am five feet and eleven inches tall, and I weigh 180 pounds. Remember that one foot is equivalent to twelve inches. Since I am five feet tall, we will multiply five with twelve to get sixty. Now, I am an additional eleven inches taller than five feet, that is, sixty inches. Hence, we will add eleven inches to sixty inches to make that seventy one inches. The formula is:

BMI = (703W)/(H^2) where BMI is the Body Mass Index, W is the weight in pounds, and H is height in inches. Since I am seventy one inches tall, we will denote that as H = 71. Since I am 180 pounds, we will denote that as W = 180. Hence, plug both of the values into the formula, which is BMI = (703*180)/(71^2). 71^2 is 71 squared which means that 71 times 71 is 5,041. 703*180 is 703 times 180 equals 126,540. Hence, we will have BMI = 126,540/5,041. Either by using the calculator or performing a long division 126,540 divided by 5,929 is approximately equivalent...

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MAT 540 Week2 Quiz
Question 1
If variable costs increase, but price and fixed costs are held constant, the break even point will decrease.
Question 2
Parameters are known, constant values that are usually coefficients of variables in equations.
Question 3
Probabilistic techniques assume that no uncertainty exists in model parameters.
Question 4
In general, an increase in price increases the break even point if all costs are held constant.
Question 5
P(A | B) is the probability of event A, if we already know that event B has occurred.
Question 6
A continuous random variable may assume only integer values within a given interval.
Question 7
The events in an experiment are mutually exclusive if only one can occur at a time.
Question 8
A bed and breakfast breaks even every month if they book 30 rooms over the course of a month. Their fixed cost is $4200 per month and the revenue they receive from each booked room is $180. What their variable cost per occupied room?
Question 9
The indicator that results in total revenues being equal to total cost is called the
Question 10
If the price increases but fixed and variable costs do not change, the break even point
Question 11
A university is planning a seminar. It costs $3000 to reserve a room, hire an instructor, and bring in the equipment. Assume it costs $25 per student for the administrators to provide the course materials. If...

...119. Explain how to solve an exponential equation when both sides can be written as a power of the same base.
When an exponential equation has both sides of the equation as the same base one needs to rewrite the equation in the form of bM=bN. For instance, 24x-3=8. To make this the same base we need to make 8 a base of two by writing it as 2^3. Then we have 24x-3=23. Then we get rid of the base and get 4x-3=3. Finally we solve for x.
4x-3=3
4x=6
x=23
120. Explain how to solve an exponential equation when both sides cannot be written as a power of the same base. Use 3x = 140 in your explanation.
To solve this equation one needs to use a natural logarithm or ln.
First take the ln of both sides, ln 3x= ln 140
Then using bx= x ln b, move the variable to the front, x ln 3 = ln 140
Solve for x, x= ln3ln140= 1.0986122887/4.9416424226 = 0.22231723680404.
121. Explain the differences between solving log31x - 12 = 4 and log31x - 12 = log3 4.
When solving log31x - 12 = 4 one needs to write it in the form of bc=M. To do this we do the following; logbM=c means bc=M.
1) log31x - 12 = 4
2) 34=x-12
3) 81=x-12
4) x=93
In the case of log31x - 12 = log3 4, since the log is the same on both sides of the equation the will be omitted. The new equation would be; 1x-12=4. Then solve as normal. Add 12 to 4 to get 16, leaving 1x, which is just x and you have x=16.
122. In many states, a 17% risk of a car accident with a blood alcohol...

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Two- Variable Inequalities
Lynwood Wright
MAT 222 Week2Assignment
Instructor: Dr. Stacie Williams
December 14, 2013
In Elementary Algebra we have learned how to solve systems of equations. The solution to a system of linear equations is the point where the graphs of the lines intersect. The solution to a system of linear inequalities is every point in a region of the graph where the inequalities overlap, rather than the point of intersection of the lines (Slavin, 2001).
This weekassignment required to solve problem 68 on page 539 (Dugopolski, 2012). I will be giving a detailed presentation on math required for the solution to this problem; the accompanying graph shows all of the possibilities for the number of refrigerators and the number of TVs that will fit into an 18-wheeler. The point-slope form of a linear equation to write the equation itself can now be used. These are the steps we take to solve our linear inequality. I will start with the point-slope form. Substitute slope form with (300, 0) for the x and y. Next we are going to use the distributive property and then add 330 to both sides and divided both sides by -3 and cancel out like terms.
The graph has a solid line rather than a dashed line indicating that points on the line itself are part of the solution set. This will be true anytime the inequality...

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Simplifying Expressions
MAT221
2a (a – 5) + 4(a – 5)
2a (a – 5) + 4(a – 5) Problem which was given
2a (a) – 2a (5) + 4(a) + 4(5) to the left Distributive Property of Addition over Multiplication
2(a a) – 2a (5) + 4(a) + 4(5) and the Associative Property of Multiplication
2(a a) – 2(5) a + 4(a) + 4(5) and the Commutative Property of Multiplication
2(a a) – (2*5) a + 4(a) + 4(5) and the Associative Property of Multiplication
2a2 – 10a + 4a + and the 20 Multiplication Properties
2a2 – 6 a + 20 and the Subtraction Property
Now on the left hand side is a step of the mathematical reasoning for 2a (a – 5) + 4(a – 5) to be simplified as 2a2 – 6a + 20. Also on the right hand side are the steps for logical reasoning. Now the middle part I used a combined because of the terms are like and the extreme terms are unlike any of the other three terms. Now the parentheses are used to show that the associative property and removed from and the multiplication and subtraction. Although the numerical coefficient must come before the literal coefficient of the problem.
2w – 3 + 3(w – 4) – 5(w – 6)
2w – 3 + 3(w – 4) – 5(w – 6) the given problem are on the
2w – 3 + 3w + 3(-4) + (-5) w + (-5)(-6) left side of the Distributive Property of Addition over the Multiplication
2w +...

...REAL WORLD RADICAL FORMULAS
Krissel Aromin
MAT222 Week 3 Assignment
5/20/2014
Introduction
In this paper I will be discussing on radical formulas and how to solve for the formula that is given as C = 4d^-1/3b where d is the displacement in pounds and b is the beam width in feet. The exponent of -1/3 means that the cube root of d will be taken and then the reciprocal of the number will be used in the multiplication. These rules include accurately finding the cube and square root for numbers and understanding the application of the solution in sailboat stability (Example, 2013).
Sailboat Stability
In this paper we will need to solve problem #103 on page 605 Sailboat Stability (Dugopolski, 2012). In order to consider safe for ocean sailing the capsize screening value C should be less than 2. For a boat with a beam (width) b in feet and displacement d in pounds, C is determined by the function C=4d-1/3b (Dugopolski, 2012). In the beginning of the problem radicals look difficult at first, but the idea ranges through exponents and order of operations. To start out the problem we have to solve a, b, and c.
a) Find the capsize screening value for the Tartan 4100, which has a displacement of 23,245 pounds and a beam of 13.5.
C=4d-1/3b
C= 4(23245)-1/3(13.5) I have plugged in the values into the formula. Allowing the order of operations, the exponents are solved first (exponent computed by calculator)....

...this podcast are experts in the field that they are talking about shows that there is validity in this podcast. Even though this podcast was recorded in 2008 it still has validity when you compare the information provided in it to research that has been conduct today.
As I stated before it is easy to access any information that you want as long as you have access to the internet. It is amazing that you can find studies of things that was conducted in other countries all because it was available on the internet. For example the University in Hong Kong did a research on how undergraduate students conduct research for their assignments. They conducted their research on eleven students. The study of the paper was based on some data collected through process logs and interviews with a small group of English as a second language students writing academic assignments at an English-medium university in Hong Kong (Li, 2012). Even though we are culturally different we all experience some of the same things. For example with this study that was conducted at a University in Hong Kong the students conduct research the same way that we do as in using the internet. There are also other countries schools.
There are many factors that anyone should consider when they are deciding on whether to use a particular internet source for the information they are researching. The factors that I look for are credibility, currency, and objectivity. When looking for...

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Financial Polynomials
MAT221: Introduction to Algebra
Financial Polynomials
Problem 90 on page 304 of the text book shares the steps and formula needed to square the binomial and multiplication for the Compounded semiannually. (Dugopolski, 2012) Using the formula provided, as well as the problems assigned, I will calculate the math to find the interest rate on an investment. This will help me in real life understand how to calculate interest on future savings. I will show all steps of the squaring of the binomial and multiplication along with any simplification which might be required to solve as I work through the math.
An expression containing numbers and variables grouped according to certain patterns is a polynomial. (Dugopolski, 2012) Like whole numbers, polynomials may be prime or factorable into products of primes. In the text the following expressions were given; P=$200 and r= 10%, and P=$5670 and r=3.5%.
To begin the math, first I will rewrite the expression without the parenthesis. This means FOIL, or multiply First, Outer, Inner, Last, the binomial:
P(1+r/2)²
P(1+r/2)* (1+r/2)*
P(1+r/2 + r/2+r²/2)
P(1+r+r²/4)
P + Pr+Pr²/4
Next I’ll evaluate the new expression by entering the figures provided in the assignment. P = $200 and r = 0.1 (10% equals 10/100 or 1/10):
P + Pr + Pr²/4
200 + 200 * (0.1) + 200*0.1)²/4
200 + 20 +...

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Buried Treasure
MAT221
Instructor
Date
Buried Treasure
In this essay of Buried Treasure we will use many different ways to attempt to factor down three expressions problems. Our first problem from our reading talks about Ahmed and Vanessa, Ahmed has half of a treasure map, which indicates that the treasure is buried in the desert 2x + 6 paces from Castle Rock. The other half of the map is in Vanessa possession and her half indicates that to find the treasure, one must get to Castle Rock. When she get there to walk x paces to the north, and then walk 2x + 4 paces to the east. I wonder what X could equal to, if Ahmed and Vanessa come together in finding the treasure they would save a lot of time of digging.
In this Pythagorean equation we will see how far Ahmed would walk 2x+6 paces and Vanessa would have to walk 2x+4, x in desert to find the Castle Rock. Ahmed and Vanessa would need equipment for their journey they will use rope, compasses and sticks with colored flags. If Ahmed use a rope tied with a stick and a colored flag to the Castle Rock using a yellow flag to mark the spot. The yellow flag mark would be basically 2x + 6 paces. Which would be a hypotenuse on the north side of the Castle Rock. Vanessa will use her compass to find south side of the Castle Rock. Where she will walk “X” paces in a straight line south toward the Castle Rock and mark the place where a red flag is...