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Transformation of E. coli by plasmid DNA

1.Table showing the results from the selective plates

|Plate |Plasmid |Contents of plates |Number of colony | | | | |White |Blue | |1 |Ligation mixture |Ampiclillin + X- gal + IPTG |10 |0 | |2 |Ligation mixture |Ampiclillin + X- gal + IPTG |11 |0 | |3 |pUC18 |Ampicillin |5 |0 | |4 |pUC18 |Ampiclillin + X- gal |0 |5 | |5 |pUC18 |Ampiclillin + X- gal + IPTG |0 |5 | |6 |UNT |Ampicillin |0 |0 |

In plate 1 and 2(i.e. ligation mixture), the presence of the white colonies shows the successful transformation of the ligation mixture to the JM101 with ampicillin resistant ability. As the lacZ’ gene was disrupted in the ligation mixture plasmid, only non-functional lacZ product can be formed and results in white colony only.

In plate 3, there is only white colonies can be observed. It shows the successful transformation of pUC18 to JM101 with ampicillin resistant ability. The absence of the x-gal and IPTG inducer leads to no blue colonies can be formed.

In plate 4, there is only blue colonies can be observed. However, it is an abnormal result we expected. The expected is that only white colonies can be formed in this plate because there is no IPTG presence in the plate leading to no α-complementation. Our...
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