Default subnet mask for class B = 255.255.0.0
Default subnet mask for class C = 255.255.255.0
The number of hosts that class A can have is 16,777,214
The number of hosts that class B can have is 65,534
The number of hosts that class C can have is 254
2)What is the subnet ID of host 22.214.171.124, given a subnet mask of 255.0.0.0? Explain your answer. Subnet ID = 126.96.36.199
The first 8 bits of the host address and set the rest of the numbers in the address to 0. 3)What is the subnet ID of host 192.168.18.145, given a subnet mask of 255.255.255.0? Explain your answer. Subnet ID = 192.168.18.0
Basically just take the last 0 off the subnet mask and put it on the end of the IP address.
4)What is the broadcast address for IP address 188.8.131.52 with a subnet mask of 255.255.0.0? Show how you determined the broadcast address. The broadcast address is 184.108.40.206
Since it’s a class B address. I took the first and second set of number from the IP address and added them to the first and second part of the subnet mask. Pushing the first 2 numbers of the subnet mask to the third and fourth spot. 5)You want to divide a class C network into 12 subnets. Which subnet mask will you use to get the most hosts on each network? How many hosts will be on each subnet? Explain your answer. Use a subnet mask of 255.255.255.240 = 16 subnets and 14 hosts per. Theres 4 bits for hosts and 4 for network numbers. Each set = 16 then just subtract one address for the network number and broadcast number for the hosts per. 6)You want to divide a class B network into 100 subnets. Which subnet mask will you use to get the most hosts on each subnet? How many hosts will be on each subnet? Explain your answer. Use a subnet mask of 255.255.254.0 = 128 subnets and...