CaCO3(s) + 2HC(aq) CaCl(aq) + H2O(l) + CO2(g)
The reaction between Hydrochloric Acid and Calcium Carbonate is being investigated because it produces a gas called Carbon Dioxide. This gas can be collected and is therefore a reliable result to base the investigation on.
VariableWhy will this variable affect the rate of gas production? Volume of HClThe more HCl used in this experiment would increase the rate of gas production, as there is more solution for the calcium carbonate chips to react with. Concentration of HClThere are more reactant particles, therefore a greater chance of them colliding. So there are more collisions, increasing the rate. Temperature of HClThe reactant particles are moving quicker and more particles have activation energy. There are more collisions, which increases the rate. Time gas collected forIf there is more time than more particles are colliding, increasing the rate of gas collected. Mass of calciumA grater mass of calcium means there are more particles to collide, increasing the rate. Surface Area of Calcium CarbonateIf the surface area is increased, there are more exposed to the other reactant. The reactant particles collide more often so the rate increases.
The dependant variable of this experiment is the volume of gas produced in a certain time. And the independent variable is the mass of calcium of calcium carbonate.
I predict that if the mass of calcium carbonate chips is increased then the reaction time will increase. Looking at my graph from the preliminary results I predict that if the mass of calcium carbonate is doubled, then the volume of gas production will double. In the preliminary experiment the gas production for 1g was 34cm3, in the second with a 2g mass the volume was 95cm3,...