Hooke’s Law: Force (Newton) = force constant * extension of the spring (Cm)

Aim: The purpose of this experiment is to test and verify that Hooke’s law is correct, which is the extension of a spring is in direct proportion with the load added to It as long as this load does not exceed the elastic limit.

Hypothesis: The weight of the object is directly proportional to the extension of the spring.

Independent variable: The weight of the object.

Dependent variable: Spring’s extension.

Controlled variable: Use the same spring for the experiment, and choose objects that have the same shape but different mass. Also make sure that the spring stays in the same height from the ground.

Materials: Round shaped object which different mass, Ruler, Spring, and Stand.

Procedure: First, the experiment starts by using a stand with the spring attach on it 30 cm from the table. Then, use a ruler to measure the spring from the very begging to the end and record the starting length. Later, attach a round-shaped object which is 50 grams on the end of the spring, and use a ruler to measure the current length. Repeat the experiment and add 50 grams more each time.

Diagram:

Data Collection:
|Weight (Newton) | |Mass of the object (Kilogram) | |Total length (Centimeter) | |Extension (Centimeter) | | | |0 N...

...Aim: To determine a value for the spring’s force constant, k.
Introduction:
Hooke’sLaw indicates the relationship between the amount of extension, e, of a spring to the size of the force, F, acing on it.
This relationship may be written as :-
F = ke
F = ke
where k is a constant for which particular spring you are using. It is the force constant of the spring.
* The force applying on the spring, F, is denoted by Newton in SI Units. (N)
* The amount of extension of the spring, e, is denoted by meters in SI Units. (m)
* The force constant of the spring, k, is denoted by Newton over meters in SI Units. (N/m or N m-1)
The variables for this experiment are as identified below:
* Independent Variable: Slotted Masses of 100 g each
* Dependent Variable: The Amount of Extension of the Spring, e
* Controlled Variable: The Elasticity of the Spring-in-Use
Diagram:
* We have set up our equipment as shown in the diagram opposite. In doing so, we made sure that the spring and meter stick hang over the edge of the bench, where the experiment is being carried out. There should be no interaction between the mass & the spring and the meter stick or the edge of the bench. This will enable us to have larger extensions of the spring.
* Counter Balance
Counter Balance
A clamp or a counter balance, such as a heavy book in this case, is preferable to use in order to provide for the balancing of the...

...INVESTIGATION OF HOOKE’SLAW –
AIM:
To investigateHooke’slaw by estimating the spring constant of a spring.
INTRODUCTION:
Hooke’slaw is a law in physics named after Robert Hooke, a British physicist who lived in the 17th century and is said to have been the first to pose the idea of this law.(wikipedia,2010) Hooke’slaw states that the Force with which a spring pushes back is linearly proportional to the distance from its equilibrium (wikepedia,2010) , this can be simplified by saying that the force acting on a spring/material is directly proportional to the extension(which is how long the spring/material has become/stretched since the force was applied) of the string/material (Breithaupt, 2010). This can be expressed as an equation.
F= -ke
Where F represents the Force (in N), e represents the extension (in m) and k is referred to as the spring constant (which is the stiffness of the spring and is unique for each spring) in N/m (Breithaupt, 2010). Many materials obey this law as long as the load applied on the material does not cause the material to exceed its elastic limit causing the material to loose its elasticity and become deformed even after the load applied has been removed. As the material exceeds its elastic limit the string begins to display a behaviour...

...An Investigation into Hooke'sLaw
Planning
The aim of this experiment is to find out if the amount of weight
applied to an elastic or stretchable object is proportional to the
amount the object's length increases by when the weight is applied.
Since Hooke'slaw is famous, and is used a lot, I have many resources
and researchable information available to use. I took this from a
website;
http://www.efunda.com/formulae/solid_mechanics/mat_mechanics/hooke.cfm
"Robert Hooke, who in 1676 stated,
The power (Sic.) of any springy body is in the same proportion with
the extension.
He announced the birth of elasticity. Hooke's statement expressed
mathematically is,
[IMAGE]
where F is the applied force (and not the power, as Hooke mistakenly
suggested), u is the deformation of the elastic body subjected to the
force F, and k is the spring constant (i.e. the ratio of previous two
parameters)."
The equation will be very useful in calculating the change in size,
and for preparing my hypothesis. I took this from
http://www.tiscali.co.uk/reference/encyclopaedia/hutchinson/m0021767.html.
Elasticity (physics)
In physics, the ability of a solid to recover its shape once deforming
forces (stresses modifying its dimensions or shape) are removed. An
elastic material obeys Hooke'slaw, which states that its deformation
is...

...Hooke’sLaw Experiment Report
Done by Yovaphine Wijaya – 11 Science 1
Aim
To investigateHooke’slaw for simple strings or rubber.
Hypothesis
The change in length of spring is directly proportional to the applied so that it will cause greater change in length of the spring for greater force applied. It is supported by the formula of force, F = kx, where F is the applied force, k is the spring constant of the spring, and x is the change in length or extension of the spring. Since the spring used is the same, the spring constant will always be the same for any value of force applied and extension of the spring.
Theory
The relationship between a load force and a light spring (F = kx) was the first determined by Robert Hooke in the 17th century. Hooke’slaw states that when an elastic material is subjected to a force, its extension (Δx) is proportional to the applied force. The value of k is constant for a particular spring. When an elastic material is subjected to a force, its extension (Δx) is proportional to the applied force, the value of k is constant for a particular spring.
Variables
Independent Variable
The applied force calculated by using the formula F = mg, where F is the applied force in Newton (N), m is the mass of the load measured by using an electronic balance in gram (g), and g is the gravitational acceleration in m/s2, which is a value constant (9.8m/s2)....

...position. If we apply Newton’s Laws to the mass attached to the spring in the figure shown below, it is clear that the gravitational force of the mass on the spring must be balanced by a force from the spring in order for the spring-mass system to remain at rest. This force is called the spring force, Fs. The spring force is an example of a type of force referred to as a restoring force. This name comes from the fact that the spring force tries to restore the spring to its original un-stretched position where it is “comfortable” (the spring doesn’t like to be stretched nor compressed).
Robert Hooke was the first to investigate the relationship between the applied force and the extension of the spring and deduced the law for elastic springs called Hooke’sLaw in his honor. His law expresses a direct relationship between the applied force and the extension of the spring. Mathematically, Hooke’slaw can be stated as Fa=k∆x. Fa stands for the applied force. The actual statement of Hooke’slaw is Fs=-k∆x, where Fs is the spring force, the negative sign indicates the restoring nature of the spring force, and k is the constant of proportionality called the spring constant (some call it the force constant) that depend on the material and number of coils of the spring; k indicates the “stiffness” of the spring – the larger the value of k,...

...Experiment 14: Hooke’sLaw and Simple Harmonic
Motion
Purpose
(1) To study Hooke’sLaw for an elastic spring
(2) To study Simple Harmonic Motion of a mass suspended from an elastic spring
Apparatus
Helical steel spring with supporting stand and scale, set of slotted weights with hanger, timer, laboratory balance.
Theory: Hooke’sLaw
A spring exerts a force which is given byHooke’sLaw:
1 Fs = - kx
where x is the amount of displacement from the equilibrium position. The negative sign in this equation shows that the spring’s force is opposite to x. If the spring is stretched (x is positive) then the spring pulls back. If the spring is compressed (x is negative) the spring pushes. The parameter k is the spring constant and is a property of the spring. It is different for different springs.
An elastic spring subjected to a stretching force of magnitude F will be stretched from its equilibrium position by an amount x given by Hooke’sLaw until the spring force, which pulls back when the spring is stretched, balances the stretching force.
If you hang your spring on the supporting stand (Figure 1), it will be at its unstretched length. Hanging a slotted weight of mass mload on it will subject it to the force of gravity on the slotted weight F= mload g. This will cause the spring to stretch...

...V. Analysis and Conclusion
In this experiment we studied the elastic properties of the spring, the Hooke’sLaw and the total work done on the spring when it is being stretch. Also, this experiment tackles the elasticity and deformation of a material that obeys the Hooke’sLaw which states that “Within the elastic limit of a body, the deforming force is directly proportional to the elongation of the body.” Our experiment is to determine the force constant of the spring. The calculations used throughout this experiment were to determine the displacement, force, and the spring constant of the spring used. In order to find the displacement, which is the amount the spring has moved out of its equilibrium position, the average of the four trials for each force exerted is needed to be found. Once the averages are confirmed, the equilibrium position average is to be subtracted from the averages. In order to calculate the force, the equation F=ma is used where the m is the mass and a is the acceleration due to gravity. The mass would be the weights so, if to be finding the force of a 0.010kg weight, the force would be 0.010*9.8 which equals 0.098. Finally, to calculate the spring constant, the force is divided by the displacement. Using the results above, 0.098(force)/0.01225(displacement) = 8.000
Experiments are bound to have errors and uncertainties. First of all, human error is the always acknowledgeable...

...Name(s)_____________________
HOOKE’SLAW and SIMPLE HARMONIC MOTION
INTRODUCTION
Any motion that repeats itself in equal intervals of time is called periodic motion. A special form of periodic motion is called Simple Harmonic Motion (SHM). Simple Harmonic Motion is defined as oscillatory motion in which the resultant force on the oscillating body at any instant is directly proportional to its displacement from the rest position and opposite in direction to its motion.
For a spring system, this can be written as F = -kx where F is the resultant force on the object attached to the spring, x is the displacement of the object from equilibrium and k is a constant called the spring constant. The force is a restoring force because it tends to restore the object back to its original position. This relationship is called Hooke’sLaw.
If a mass is attached to a spring and then displaced from its rest position and released, it will oscillate around that rest position in simple harmonic motion. The period T of the oscillating system does not depend on the displacement from rest as long as the spring is not overstretched. The period is the time it takes for as system to go through one full oscillation and return to its starting position.
In this lab we will study Hooke’sLaw for a mass connected to a spring and then investigate the SHM of the mass on the spring....