1. The researchers found a significant difference between the two groups (control and treatment) for change in mobility of the women with osteoarthritis (OA) over 12 weeks with the results of F(1, 22) = 9.619, p = 0.005. Discuss each aspect of these results. The F-value is high enough at the 5% level of significance to suggest a significant difference between the control and treatment groups. The p-value 0.005 < 0.05 hence this suggests a rejection of the null hypothesis, meaning that the control and treatment groups are found to be different.

2. State the null hypothesis for the Baird and Sands (2004) study that focuses on the effect of the GI with PMR treatment on patients’ mobility level. Should the null hypothesis be rejected for the difference between the two groups in change in mobility scores over 12 weeks? Provide a rationale for your answer.

The null hypothesis is that the mean mobility scores for both groups are the same. As stated previously, since the p-value 0.005 < 0.05 this means I reject the null hypothesis. So the mean "difficulty with mobility score" for both groups must be different.

3. The researchers stated that the participants in the intervention group reported a reduction in mobility difficulty at week 12. Was this result statistically significant, and if so at what probability?

Yes the result was statistically significant at probability p < 0.001, according to the text.

4. If the researchers had set the level of significance or α = 0.01, would the results of p = 0.001 still be statistically significant? Provide a rationale for your answer.

Yes this still implies statistical significance because 0.001 < 0.01

5. If F(3, 60) = 4.13, p = 0.04, and α = 0.01, is the result statistically significant? Provide a rationale for your answer. Would the null hypothesis be accepted or rejected?

In this case the result would not be considered statistically significant because 0.04...

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HLT362 Week 1 -5 All Discussion Questions
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Week 1 Dqs
1 - How could graphics and/or statistics be used to misrepresent data? Where have you seen this done?
2 - What are the characteristics of a...

...Week 4
Exercise36
1. F is the statistic for ANOVA and the group df=1 and the error for df is 22. The f ratio is 9.619, which is significant for 0.005.
2. I would reject the null hypothesis because p=0.005 which is less than 0.05. This suggests there is a difference between the 2 groups.
3. There was a significant reported change of the p<0.0001 at week 12 compared with the control group, which there was no change.
4. Yes because 0.001<0.01 which is...

...months t ratios for the variable Exercise from Table 3. What is your
conclusion about the long-term effect of the health-promotion intervention on Exercise in this study?
Answer: t=-7.75* (3months) and t= -3.93* (6 months). At 3 months, the difference in exercise from pretest was statistically significant with t = - 7.75*, P< 0.05. At 6 months the difference in exercise from pretest was also statistically significant with t = -3.93*. The...

...1. The researchers found a significant difference between the two groups (control and treatment) for change in mobility of the women with osteoarthritis (OA) over 12 weeks with the results of F(1, 22) 9.619, p 0.005. Discuss each aspect of these results.
Answer: Since the F value is significant, based on the p-value of 0.005 which is less than 0.05 which is sufficient to reject the null hypothesis. This suggests that there is a difference in the control and treatment groups.
2. State the...

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HLT362 Module 1 Exercise 16
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1- The researchers analyzed the data they collected as though it were at what level of measurement? (Your choices are: Nominal, Ordinal, Interval/ratio, or...

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HLT362 Module 5 Exercise 27 Simple Linear Regression
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What are the independent and dependent variables in Figures 2, A, B, and C? How would you describe the relationship between the...

...EXERCISE36 Questions to be Graded
1. The researchers found a significant difference between the two groups (control and treatment) for change in mobility of the women with osteoarthritis (OA) over 12 weeks with the results of F (1, 22) = 9.619, p = 0.005. Discuss each aspect of these results.
Answer: The F value suggests there is a significant difference between the results of the control and treatment groups. The P-value of 0.005 is < the alpha of 0.05.This...

...EXERCISE36 Questions to be graded
1. The researchers found a significant difference between the two groups (control and treatment) for change in mobility of the women with osteoarthritis (OA) over 12 weeks with the results of F(1, 22) = 9.619, p = 0.005. Discuss each aspect of these results.
* The F-value suggests that there is a significant difference between the results of the control and treatment groups. The P-value of 0.005 is < the alpha of 0.05. This...