Michelle Faktor and Kelly Freas
Date of Experiment: October 28, 2012
Purpose: The purpose of this lab is to observe the reactions of halide ions with different reagents by mixing them together. Analyze data to determine characteristic reactions of each halide ion. Infer the identity of unknown solutions.
* 0.1 M AgNo3
* 0.1 M NaCl
* 0.1 M NaF
* 0.2 M KBr
* 0.2M Kl
* 0.2 M Na2S2)3
* 0.5 M Ca(NO3)2
* 3% Starch solution
* 5% NaOCl ( commercial bleach)
* 12 test tubes, 18 mm X 150 mm test tube rack
1. Place the 4 solutions in separate test tubes with about 2.5 mL in each. (NaF, NaCl, KBr, KI) Use a dropper or you can use a pipette. Add 1 Ml ( 20 drops) of 0.5 M Ca ( NO3h) to each test tubes. Observe and record. Make sure to note which one DID NOT precipitate. 2. Drain the 4 test tubes and refill them with clean solutions. (NaF, NaCl, KBr, KI) This time add 2.5 mL (20 drops) of 0.1 M AgNo3 to each of the test tubes. Observe and record in the data table. 3. This time do not drain the already mixed solutions. Add 2.5 mL of 0.2 Na2S2O3 and record your observations. 4. Drain the test tubes and refill with (NaF, NaCl, KBr, KI) Add 2.5 mL of 3% starch to each test tube, Afterword add a drop or 2 of 5% NaOCI (commercial bleach). Record observations 5. Get the 2 unknown solutions and repeat steps 1-4.
Data/Observations: Refer to Data Table
NaF = sodium fluoride
NaCI= table salt
KBr= Potassium bromide (KBr) is a salt
KI= Potassium Iodide
Ca(NO3)2= Calcium nitrate
AgNO3= Silver nitrate
Both sodium fluoride and calcium nitrate are salts formed from strong acid and strong base. When any such salt dissolves in water, it completely dissociate into ions. For the ions to react, however, either precipitation would occur. The reason why sodium fluoride and calcium nitrate would react is because calcium fluoride is insoluble in...