Objective: To gain experience in gathering and displaying data from a simple experiment Materials: Meter stick, tape, and a ball is needed to perform this experiment. Theory: The graph of function is the collection of all ordered pairs graphing on a cartesian plane is sometimes referred to as a curve sketching. Experimental Procedures:

Position a meter stick vertically on a flat surface, such as a wall or the of a lab bench. be sure the metric scale of the meter stick is on the outside and secure the meter stick to the wall or lab bench with two strips of masking tape. You will then take a ball as close to the meter stick as possible and measure a) the height dropped and b) the resulting height bounces. Repeat this for three different heights dropped and records all data. Then you will make a graph of the data. Make at least three more measurements for each of the previous three height dropped levels. Find the average height bounced for each level and record the data and the average values. Make a new graph of the average height bounced for each level that the ball was dropped . Draw a straight line best fit that includes the origin by considering the general trend of the data points measurement data. Draw that straight line as close as possible to as many data points as you can so that you have about the number of data points on both sides of the straight line. Compare how well both graph predicts the heights that the ball will bounce for height dropped that were not tried previously. Located an untried height dropped distance on the straight line then use the corresponding height bounced from the graph as a prediction.

...StraightLine Equations and Inequalities
A: Linear Equations - Straightlines
Please remember that when you are drawing graphs you should always label your axes and that y is always shown on the vertical axis. A linear equation between two variables x and y can be represented by y = a + bx where “a” and “b” are any two constants. For example, suppose we wish to plot the straightline If x = -2, say, then y = 3 + 2(-2) = 3 - 4 = -1 If x= -2 -1 -1 1 0 3 1 5 2 7 As you can see, we have plotted the five points on the graph. They do indeed all lie on a straightline and we have joined them together to show the line. Of course, you could draw the line by just plotting any two points on it and then joining and extending those two points. y = 3 + 2x ..... and so on (see table below)
Then y =
y
x
The equation simply represents the relationship between two variables x and y. For example: suppose our basic salary is £4000 and we add commission to that at the rate of 5% of our total sales. Call y our total salary and call x our sales (both in £) then we could represent this relationship as y = 4000 + 0.05x (5% is five hundredths i.e. 0.05) Then, if we knew that total sales were 6000, we could work out total salary: y = 4000+0.05(6000) or £4300
For our next example, we will draw the equation y = 6 - x on a graph (using just two...

...company chooses to incorporate should be one that most effectively matches expenses with the revenues produced. The method that most select is that of straight-line depreciation, which "spreads the depreciable value evenly over the useful life of an asset." (Horngren, Sundem, Elliott, & Philbrick 2006, p.342) Depreciation schedules reflect how much depreciation will be allocated for each year of the assets useful life. In order to calculate depreciation expense we take the cost of the acquisition minus the estimated residual value divided by the years of estimated useful life. The depreciation schedule using the straight-line method for Balls and Bats, Inc. would be as follows:
Total Acquisition cost= $100,000
Salvage value= $10,000
Estimated useful life= 4 years
Depreciation expense= 100,000 - 10,000 = 22,500
4
D= $22,500 per year
Single-line Depreciation
Balances at End of Year
1 2 3 4
Acquisition cost of
Equipment $ 100,000 $100,000 $100,000 $100,000
Accumulated Depreciation $ 22,500 $ 45,000 $ 67,500 $ 90,000
Net book value $ 77,500 $ 55,000 $ 32,500 $ 10,000
Balance at the end of year 4 equals salvage value of $10,000
Assets that shows a pattern of depreciation that is written off more quickly than regular straight-line method is referred to as accelerated...

...method? Assume a depreciation rate of twice the straight – line method.
Straightline method =- (cost-residual value) = 25000-5000
10 10
Depreciation per year = 2000
Depreciation after year 2 = 2000+2000=$4000
Book value at year 2 = $25,000-4000=$21,000
Answer: $21,000
16.
Q= Pete’s Warehouse has a market value of $5,000,000. The property in Pete’s area is assessed at 40% of the market value. The tax rate is $105.10 per $1,999 of assessed value. What is Pete’s property tax?
$5,000,000*40%=$2,000,000 assessed value
105.10*1.999=210094.90
$2,000,000/1999*105.10=105,152.576
Answer:Property tax =$ 105,152.58
17.
Q= Jim Smith, who lives in Territory 5 carries 10/20/5 compulsory liability insurance along with optional collision that has a $200 deductible. Jim was at fault in an accident that caused $1,800 damage to the other auto and $600 damage to his own. Also, the courts awarded $13,000 and $8,000 respectively, to the two passengers in the other car for personal injuries. How much does the insurance company pay, and what is Jim’s share of responsibility?
18. -
Q= Jeff Sellers bought 200 shares of Radio Shack stock at $22.35. Eight months later, he sold the stock at $31.76. Assuming a 2% charge, what is the bottom line for Jeff?
Shares bought = 200
Unit cost per share = $22.35
Cost = $200*22.35=$4,470
8 months later sale price = 200*$31.76= $6,352
2%charge =$...

...“Insert → Chart” 3. Start to configure the chart. We want a XY Scatter Point Graph with Lines. You can choose Line Graph, but formatting it is more of a headache. Go ahead and add axis labels and the chart title now. At this point it should resemble what you see above. Mess with the colors and symbols as you see fit. 4. To scale the Y Axis: double click on the region where the number labels are. You should get a formatting window where you can adjust the scale. (I.E in my graph, the Minimum = 55, the Maximum = 85, and the Interval = 2.5). You should be able to leave the X Axis alone. If not, do the same to rescale it as you see fit. 5. Calculate Δ Tfp as shown in the lab handout using your nifty graph!
Time (Seconds) 20 40 60 80 100 120 140 160 180 200 220 240 260 280 300 320 340 360 380 400 420 440
Pure BHT 74.1 72.8 72.1 71.2 71.1 69.6 70 70.3 70.4 70.4 70.4 70.4 70.5 70.5 70.5 70.5 70.5 70.5
BHT + pdB 77 74.2 72.1 70.2 68.6 67 65.2 64 62.6 61 60.5 60.5 60.4 60 59.7 59.4
BHT + ??? 83 83.2 80.8 78.9 76.1 74.8 72.7 71.2 69.4 68 66.6 64.3 63.5 61.7 60.5 59.1 58.1 58.5 58.1 58.4 57.1 57.7
Troubleshooting/FAQ AKA Problems That You May or May Not Encounter Q: My Graph is just a bunch of dots or its just lines. A: Double click on your graph and find your way to a “Chart Type” (or something to that effect) formatting box. Double check that you have an XY scatter point graph with lines. If not, change it into...

...in each module. By implementing a SOA system Peachtree can use input from the doctors, both young and old, and tailor the system to meet their needs. In order for Peachtree to have the greatest success with a SOA based system, as the pros for SOA greatly outweigh the pros for a monolithic system
1. provide quickness
2. provide flexibility to go after selective standardization
3. can attempt on a limited scale or move to reduce tisk
4. cost flexible due to immature SOA market
SOA disadvantages
With a SOA based system the costs, challenges, and to some extent, benefits are largely unknown in a healthcare setting
1a couple fo years from being ready
2. immature market, no industry record
3. risk of becoming victim of ongoing learning curve
4.no one else is aggressively adopting SOA
Difficult to estimate time to achieve progress
Monotholic Advantages
A monolithic IT system would allow Peachtree to implement standard procedures across all hospitals with little risk of system failure. The monolithic approach has been implemented time and time again, therefore the costs, challenges, and benefits are known. Using a monolithic system would reduce this risk, but by locking the doctors into standardized procedures the quality of care would decrease, going against Peachtree’s business model.
1 get the job done
2.creates new consistent infrastructure
3.single set of system that unifies everything
Peachtree Healthcare can become a single institution...

...Collin Doyle
Mrs. Perino
Math 48A.01
11 January 2013
Homework 1.2: P. 19-21 #’s 23-24, 66-67, 70, 73, 74a-b, 76
23) Problem: Explain how to determine whether a parenthesis or a square bracket is used when graphing an inequality on a number line.
Solution: a. Parenthesis: indicate a range of values, open interval, I think of parenthesis as being the parent that is more open to given their child toys and bending the rules.
b. Brackets: has limits between two numbers, closed interval, I think of brackets as the stern parent who enforces the rules to the highest degree.
24) Problem: The three-part inequality a < x < b means “a is less than x, and x is less than b.” Which one of the following inequalities is not satisfied by some real number x?
A. -3 < x < 5 B. 0 < x < 4
C. -3 < x < -2 D. -7 < x < -10
Solution: D, because -10 is less than -7 and x is greater than -7 which also means that x is also greater than -10.
66) Problem: If f(3) = -9.7, identify a point on the graph of f.
Solution: (3,-9.7), f(3) is f(x) which means that 3 is the x-value and -9.7 is the y-value.
67) Problem: If the point (7,8) lies on the graph of f, then f(___) = ____.
Solution: f(7) = 8, this problem is the reverse of the problem before, you plug in the x-value (7) into x in f(x) and then plug in the y-value (8) in for the y.
70) Problem: Use the graph of y = f(x) to find each...

...STRAIGHTLINE MODEL
In many investigations, two or more variables are observed for each experimental unit in order to determine:
1. Whether the variables are related.
2. How strong the relationships appear to be.
3. Whether one variable of primary interest can be predicted from observations on the others.
Regression analysis concerns the study of relationships between quantitative variables with the object of identifying, estimating, and validating the relationship. The estimated relationship can then be used to predict one variable from the value of the other variable(s). In this article, we introduce the subject with specific reference to the straight-line model. Here, we take the additional step of including the omnipresent random variation as an error term in the model. Then, on the basis of the model, we can test whether one variable actually influences the other. Further, we produce confidence interval answers when using the estimated straightline for prediction. The correlation coefficient is shown to measure the strength of the linear relationship. One may be curious about why the study of relationships of variables has been given the rather unusual name “regression.” Historically, the word regression was first used in its present technical context by a British scientist, Sir Francis Galton, who analyzed the heights of sons and the average heights of their parents. From his...