# Force and Movie Batman Leaps

Topics: Force, Classical mechanics, Mass Pages: 1 (445 words) Published: November 26, 2012
Superheroes have been around for a time now, since 1934 starting with Mandrake the Magician made by Lee Falk, and then came Superman made by Joe Shuster and Jerry Siegel. But how do superheroes do what they do? They play mind tricks, can lift up incredible amounts of weight and do stuff no regular human can do. In this paper I’m writing you will see how superheroes violate Newton’s 3 laws of motion. First let’s talk about batman and the movie that just came out called the dark night rises. In this movie batman leaps from a building for 4 to 5 seconds before opening his wings neglecting significant air resistance (this affect Newton’s 3rd law). Scientists found out that all that force applied exert about 1600 pounds of force to his arms. Not even the worlds strongest man can lift that much!! Next we talk about spider-man and his trickery. In his the movie spider-man 3 is basically immortal, never dying person. For example In a climatic battle scene spider man fall 80 stories and survives without breaking a bone, concussion, or presumably any internal bleeding. Lets use Newton’s second law to calculate (Fnet=ma) how much force the ground exerts on spider-man upon impact. After calculation we see that the weight of that fall is 47 tons. Wow if that any one else they would have die. Lastly we talk about the science of star trek (Kirk’s magic fingers). In the trailer we see that James T. Kirk is driving a car which is going about 80 mph (36 m/s). the car seems to be about 30 meters from edge when it starts skidding through dirt and sand. Newton second law says Fnet = Ffriction = µmg = ma where the acceleration of the car is completely due to the friction force. M is the mass of the car, g is equal to the acceleration due to gravity (9.8m/s2) , µ is the coefficient of sliding friction between sand and tires (0.5 at most), and a is the acceleration of the car. Solving for a we get: a = µg = (0.5)(9.8m/s2) = 4.9 m/s2If we assume a relatively constant acceleration then...