EXPERIMENT NO. 10
COMPOSITION OF POTASSIUM CHLORIDE
The aim of the experiment was to look for the percentage composition of the elements present in the decomposition of potassium chlorate (KClO3) and to find out what the residue after heating was. After performing the experiment the researchers found out that there were about 66.14% of potassium chloride (KCl) in KClO3, and they also deducted that the residue was actually KCl. _____________________________________________________________________________________
Total mass of the Element/Compound (Part)Total mass of Compound (Whole) × 100 The formula above is the formula used to determine the percentage composition of an individual element in a compound. In this experiment, the researchers are both going to solve for the theoretical percentage composition and the experimental percentage composition of elements/ ions. The theoretical percent composition is solved using a known formula compound and an experimental percent composition is solved using data identified in the experiment. The goal of this experiment is to formulate a diminutive percentage error as possible, which is solved using the formula below. Theoretical value-Experimental valueTheoretical value × 100 The compound that they are going to use in this experiment is KCl or potassium chlorate. Potassium chlorate, when heated to high temperatures would form this equation: 2KClO₃ (s) ∆ 2KCl (s)+3O₂ (g)
The experiment was composed of two parts. The first part was for determining the percentage composition of potassium chlorate. First, the researchers made sure that the crucible, which would be used throughout the experiment, was dry, so they heated it on a clay triangle for 2-3 minutes. Next, they let the crucible cool down a bit and then weighed it together with its cover. Then they added 1.196 g of potassium chlorate into the crucible, placed its lid and then...