Purpose:
To investigate and compare the potential energy, kinetic energy and speed of a cart on a hill 1 kg

h
1 m

Materials:
1.
2. Cart & 1 kg mass
3. Board
4. Timer
5. Metre ruler
6. Tape

Data Table:
With 1 kg mass:
Trial #| Distance(m)| Time(s)|
1| 1m| 0.41s|
2| 1m| 0.45s|
3| 1m| 0.44s|

Without 1 kg mass:
Trial #| Distance(m)| Time(s)|
1| 1m| 0.42s|
2| 1m| 0.48s|
3| 1m| 0.45s|

Calculations:

With 1 kg mass:
Average time = 0.4333s
Average velocity = Distance ÷ Average time = 1m ÷ 0.4333s ≈ 2.308m/s Total mass = (7.5N ÷ 9.8N/kg) + 1kg ≈ 1.765kg
Height = 0.33m
Kinetic energy = ½ mv2 = ½ × 1.765kg × (2.308m/s)2 ≈ 4.70J Potential energy = mgh = 1.765kg × 9.8N/kg × 0.33m = 5.71J Without 1 kg mass:
Average time = 0.45s
Average velocity = Distance ÷ Average time = 1m ÷ 0.45s ≈ 2.236m/s Mass = 7.5N ÷ 9.8N/kg ≈ 0.765kg
Height = 0.33m
Kinetic energy = ½ mv2 = ½ × 0.765kg × (2.236/s)2 ≈ 1.91J Potential energy = mgh = 0.765kg × 9.8N/kg × 0.33m = 2.47J

Analysis Questions:

How did the potential and kinetic energy compare (top and bottom of the hill)? Explain using law of conservation of energy. (use values of KE and PE for cart with mass attached) According to the law of conservation of energy, in an isolated system, the initial potential energy and the kinetic energy should be the same. However, when we were doing the experiment, we could not guarantee for ideal situation with no extra resistance, so the data above, which shows that there is difference between the two energies...

...conservation of mechanical energy
Section: 8
Name: Ahmed Atari
University ID: 201103848
Instructor: Ahmed Zainelabdin
Submission date: May 1, 2014
Objective: the purpose of this lab is to investigate the law of conservation of energy. This can be achieved by measuring both potential and kineticenergy through the experiment conducted.
Back ground:
Kineticenergy is said to be the energy of motion. Kineticenergy can be defined through this equation:
KE=12mv2 (equation 1)
Where m is the mass of the object in motion, and v is the velocity of the moving object.
Potentialenergy is the energy associated with the forces that depend on the position of the object. However, there are specific types of potentialenergy and in this lab we will consider gravitational potentialenergy. Gravitational potentialenergy is the energy possessed by the objected due to earth's gravity. This can be specifically defined by the equation:
PEgrav=mgy (equation 2)
Where m is the mass of the object, g is the acceleration due to gravity and y is the height of the object.
With...

...
PotentialEnergy:
Potentialenergy is the stored energy of position possessed by an object.
PotentialEnergy Formula :
PotentialEnergy: PE = m x g x h
Mass:
Acceleration of Gravity:
Height:
where,
PE = PotentialEnergy,
m = Mass of object,
g = Acceleration of Gravity,
h = Height of object,
Examples:
1. A cat had climbed at the top of the tree. The Tree is 20 meters high and the cat weighs 6kg. How much potentialenergy does the cat have?
m = 6 kg, h = 20 m, g = 9.8 m/s2(Gravitational Acceleration of the earth)
Step 1: Substitute the values in the below potentialenergy formula:
PotentialEnergy: PE = m x g x h
= 6 x 9.8 x 20
PotentialEnergy: PE = 1176 Joules
2. On a 3m ledge, a rock is laying at the potentialenergy of 120 J. What will be the mass of the rock.
PE = 120 J, h = 3m, g = 9.8 m/s2(Gravitational Acceleration of the earth)
Step 1: Substitute the values in the below Velocity formula:
3. A ball of mass 2 Kg is kept on the hill of height 3Km. Calculate the potential...

...Potential and KineticEnergylabreport
Caty Cleary
4th period
Problem statement:
How does the drop height (gravitational potentialenergy) of a ball affect the bounce height (kineticenergy) of the ball?
Variables:
Independent variable- drop height
Dependent variable- bounce height
Controlled variables (constants) - type of ball, measurement(unit), place bounced, and the materials used for each experiment.
Hypothesis:
If the gravitational potentialenergy (drop height) of the ball is increased, then the kineticenergy (bounce height) will increase because the ball will pick up speed on its way down which will cause it to apply more force to the ground, making the ball bounce higher.
Materials and Procedure:
Ball(s), meter stick, balance and a flat surface.
Procedure-
1. Tape the meter stick to the side of the table with the 0-cm end at the bottom and the 100-cm end at the top. Be sure that the meter stick is resting flat on the floor and is standing straight up.
2. Choose a ball type and record the ball type in the data table.
3. Use the triple beam balance to determine the mass of the ball and record the ball’s mass in the data table.
4. Calculate the gravitational potentialenergy (GPE)...

...horizontal frictionless surface a puck of mass m initially at speed u collides head-on (without rotation) with a stationary puck of mass M. Find the velocities of both puck after the collision if: i) the collision is fully elastic ii) the collision if fully inelastic. i) momentum: kineticenergy: mu = mv+MV (+ve in direction of initial u) 1 /2 m u2 = 1/2 m v2 + 1/2 M V2
2 eqns in 2 unknowns: V = (u - v) m/M substitute in K eqn: u2 = v2 + (M/m) V2 = v2 + (M/m) (u - v)2 (m/M)2 = v2 + (u - v)2 (m/M) let ρ = (m/M) ⇒ v2 (1 + ρ) - 2ρ u v + u2 (ρ - 1) = 0 quadratic eqn: b2-4ac = 4ρ2 u2 - 4 (1 + ρ) (ρ - 1) u2 = 4ρ2 u2 - 4 (ρ2 - 1) u2 = 4u2
v = [2ρ u ± (4 u2)1/2]/{2 (1 + ρ)} = [2ρ u ± 2 u]/{2 (1 + ρ)} = u (ρ ± 1)/(1 + ρ) + ⇒ v = u , and V = 0 (no collision occurs!) - ⇒ v = u (ρ - 1)/(1 + ρ) , and V = ρ (u - v) = 2ρ2 u/(1 + ρ) e.g. ρ = 1 ⇒ v = 0, V = u . as ρ → 0 ⇒ v → - u , V → 0
ii) momentum: let ρ = (m/M) kineticenergy: ratio: then
m u = (m + M) v v = u 1/(1 + 1/ρ)
1
⇒
v = u m/(m + M)
before: K1 =
/2 m u2 ,
after:
K2 =
1
/2 (m + M) v2
K2/K1 = (1 + 1/ρ) v2/u2 = 1/(1 + 1/ρ) ⇒ v = u/2 , K2/K1 = 1/2 . as ρ → 0 ⇒ v → 0 , K2/K1 → 0
e.g. ρ = 1
2) A point mass m swings under gravity from a fixed pivot on a massless cord through an angle θ to collide with a stationary block of mass M. Assuming a fully elastic...

...WORK and ENERGY
Work done by a constant force
1- The drawing shows a plane diving toward the ground and then climbing back upward. During each of these motions, the lift force acts perpendicular to the displacement , which has the same magnitude, 1.7 × 103 m, in each case. The engines of the plane exert a thrust , which points in the direction of the displacement and has the same magnitude during the dive and the climb. The weight of the plane has a magnitude of 5.9 × 104 N. In both motions, net work is performed due to the combined action of the forces , and .
a. Is more net work done during the dive or the climb? Explain.
b. Find the difference between the net work done during the dive and the climb.
Answer:
a. More net work is done during the dive.
b. 6.8 × 107 J
2- Find the work done by a force through a displacement of 3m in the positive x direction
Work-Energy theorem and kineticenergy
3- The mass of the space probe is 474-kg and its initial velocity is 275 m/s. If the 56.0-mN force acts on the probe through a displacement of 2.42×109m, what is its final speed?
Answer:
4- Example 2: Skier
Gravitational PotentialEnergy, Conservative versus Nonconservative Forces
5- The gymnast leaves the trampoline at an initial height of 1.20 m and reaches a maximum height of 4.80 m before falling back...

...with easy to
understand operating instructions. If, however, you do
encounter a question that is not covered in this Guide you
should call the LIFEBREATH dealer who installed your
furnace. Chances are that he will be able to give you a satisfactory answer but if he is unable to do so then we invite
you to contact us directly.
Airia Brands Inc.
Overview of the Air Handler
Hydronic Coil
and Pump
Compartment
Aircom
Electronics
and Fan
Compartment
3
Description and Purpose
required to be at a higher temperature than for other uses, an
anti-scald valve shall be used to ensure water for other uses
is reduced in temperature to minimize a scald hazard potential.
Combining two or more end uses such as space heating and
the heating of domestic hot water in a single system has the
potential to increase efficiency and reduce overall capital
costs. However, the proper design, installation, and commissioning of these systems are critical if these advantages
are to be realized.
This manual provides a guideline of good engineering practice in the design, installation and commissioning of
Integrated Combo Systems. The guidelines in the manual
are designed for residential forced warm air Integrated
Combo Systems which utilize domestic water heaters or
boilers and the LIFEBREATH furnace. Heating and cooling
loads shall be calculated in accordance with recognized
Residential Heat Loss and Heat Gain Calculation methods....

...Analysis of Energy Drinks and Other Beverages - LabReport
Discussion and Analysis
As a result of conducting various qualitative chemical analysis tests, Monster Energy ® was found to contain a large amount of reducing sugars and NaCl. It was found to be void of proteins and lipids. Further, Canada Dry ® gingerale was found to contain a large amount of reducing sugars, while being void of protein, lipids and NaCl.
The components of the Monster Energy drink tested were quite congruent to the components found in the other energy drinks. The exceptions, however, were that SugarFree Rockstar, like the name suggests, contains no traces of sugar, unlike Monster Energy. Also, unlike other energy drinks, Monster Energy contained detectable traces of sodium chloride.
The components of gingerale were also quite similar to the components found in other beverages. However, it contained no protein or lipids, unlike chocolate milk, and had a large amount of simple sugars, unlike Vitamin Water and Tea.
In short, the chemical assays do not fully support the marketing claims made by the energy drink producers. They show that none of the energy drinks tested contain proteins, which build, maintain and help replace tissues in the body. Also, all energy drinks (with the exception of Sugar Free Rockstar) showed...

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