Determination of Density Analysis Sheet

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  • Topic: Volume, Density, Percent difference
  • Pages : 3 (785 words )
  • Download(s) : 392
  • Published : March 19, 2012
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1. DATA:
Table 1: Density based on dimensional analysis
Trial 1Trial 2Trial 3Units
Mass of sample70.546670.546770.5465g
Dimensions of sampleLength4.984.984.99cm
Width1.211.221.21cm
Height1.211.221.22cm
Volum of sample7.297.417.37cm^3
Density of sample (based on dimensional analysis)9.689.529.57g/cm^3

Table 2: Density based on the displacement of water
Trial 1Trial 2Trial 3Units
Mass of sample70.546770.546570.5466g
Final volume of the water in the buret (Vf)29.8313.1125.51ml Initial volume of the water in the buret (Vo)14.622.6113.18ml Volume of the water dispensed from the buret (Vb=Vf-Vo)15.2110.5012.33ml Volume of water level on graduated cylinder: Vgc23.519.219.8ml Volume of sample8.298.707.47cm3

Density of sample8.508.119.44g/cm^3

2. CALCULATIONS
a. Relative Percent Error = IAbsolute ErrorI/True Value X 100% IAbsolute ErrorI = ITrue Value - Measured ValueI
The Measured Value in my experiment based on table 2 is [(8.50+8.11+9.44)/3]= 8.68 g/cm^3 The True Value is 8.94 g/mL
Absolute Error = 8.94 - 8.68 = 0.26
Relative Percent Error = (0.26/8.94)x100=2.91 Using the correct number of significant figures, gives us the answer: 3%

b. Density of metal bar using dimensional analysis
D = Mass/Volume (g/cm^3)
V = LxWxH = 4.98x1.21x1.21 = 7.29
D = 70.5466g/7.29cm^3 = 9.68 g/cm^3

c. Density of metal bar using displacement of water
D = Mass/Volume (g/cm^3)
V = Volume of water level on graduated cylinder - Volume of the water dispensed from the buret V = 8.29 cm^3
D = 70.5467g/8.29cm^3 = 8.50 g/cm^3

3. RESULTS
"The relative percent error for the density of the metal bar by displacement of water on my experiment was 2.91%. Some possible sources of error that may have contributed to my percentage error could be related to mass...
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