Computing Past Paper

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  • Topic: GCE Advanced Level, General Certificate of Secondary Education
  • Pages : 4 (624 words )
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  • Published : April 2, 2013
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UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS
GCE Advanced Subsidiary Level and GCE Advanced Level

MARK SCHEME for the May/June 2011 question paper for the guidance of teachers

9691 COMPUTING
9691/23 Paper 2 (Written Paper), maximum raw mark 75

This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the details of the discussions that took place at an Examiners’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes must be read in conjunction with the question papers and the report on the examination.

• Cambridge will not enter into discussions or correspondence in connection with these mark schemes.

Cambridge is publishing the mark schemes for the May/June 2011 question papers for most IGCSE, GCE Advanced Level and Advanced Subsidiary Level syllabuses and some Ordinary Level syllabuses.

Page 2 1 (a) – – – – – – – – (b) Attempt

Mark Scheme: Teachers’ version GCE AS/A LEVEL – May/June 2011 sensible request space to enter password space for attempt counter suitably labelled login message space title bar label return button use of all screen / well laid out / logical sequence

Syllabus 9691

Paper 23

[5]

Password

Password =”poppy”

Attempt =3

Password =”poppy” OR Attempt=3

Output

1 poppy 2 True False True password correct [1]

© University of Cambridge International Examinations 2011

Page 3 (c) Attempt

Mark Scheme: Teachers’ version GCE AS/A LEVEL – May/June 2011

Syllabus 9691

Paper 23

Password

Password =”poppy”

Attempt =3

Password =”poppy” OR Attempt=3

Output

1 cat 2 False False False poppy 3 True True True password correct 1 mark for correct value at first condition 1 mark for correct value at 2nd condition 1 mark for correct value at 3rd condition 1 mark for correct logic...
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