ATOMIC WEIGHT OF MAGNESIUM LAB
The purpose of this lab experiment is to determine the atomic weight of magnesium by measuring the amount of hydrogen gas evolved when hydrochloric acid reacts with magnesium. The reaction is as followed: Mg + 2HCL H2 + Mg2+(aq) + 2Cl-(aq) In this experiment there is a one to one relationship between the number of moles of hydrogen gas evolved and the moles of magnesium metal consumed in the reaction. Therefore in the finding of the experiment moles of H2 evolved is equal to the moles of Mg consumed, and atomic weight of Mg is equal to the weight of Mg consumed per moles of H2 evolved.
1st. Obtain a 600ml beaker, add 300ml of water
2nd. add 30ml of HCl (2M) to the beaker and stir
3rd. add 10mg of Magnesium metal to the beaker
4th. Allow hydrogen gas to evolve, all of the magnesium should be consumed. 6th. Record the amount of hydrogen gas evolved using the chemical property dialog.
Observations and Results
Moles of hydrogen evolved: 0.000829g (8.29 x 10-4)/ 0.000411 moles, (4.11 x 10-4)
Calculated atomic weight of magnesium: ______________
Atomic weight of Mg = weight of Magnesium/moles of H2
Moles of H2 evolved = moles of Mg consumed
Atomic weight of Mg= /0.000411moles
During my observation I noticed that when 10mg of magnesium metal was added to the beaker a shaded area appeared on the bottom of the beaker. When the bubbles stopped and the shaded area in the beaker disappeared it showed that the magnesium has been consumed.
< Within a few sentences, provide a concluding statement about the results of your laboratory>