Chapter 9 Estimation and Confidence Intervals
30. A random sample of 85 group leaders, supervisors, and similar personnel revealed that a person spent an average 6.5 years on the job before being promoted. The population standard deviation was 1.7 years. Using the 0.95 degree of confidence, what is the confidence interval for the population mean? A) 6.99 and 7.99 B) 4.15 and 7.15 C) 6.14 and 6.86 D) 6.49 and 7.49 Answer: C 31. The mean weight of trucks traveling on a particular section of I-475 is not known. A state highway inspector needs an estimate of the mean. He selects a random sample of 49 trucks passing the weighing station and finds the mean is 15.8 tons. The population standard deviation is 3.8 tons. What is the 95 percent interval for the population mean? A) 14.7 and 16.9 B) 13.2 and 17.6 C) 10.0 and 20.0 D) 16.1 and 18.1 Answer: A 41. Suppose 1,600 of 2,000 registered voters sampled said they planned to vote for the Republican candidate for president. Using the 0.95 degree of confidence, what is the interval estimate for the population proportion (to the nearest tenth of a percent)? A) 78.2% to 81.8% B) 69.2% to 86.4% C) 76.5% to 83.5% D) 77.7% to 82.3% Answer: A Use the following to answer questions 81-83: A student wanted to quickly construct a 95% confidence interval for the average age of students in her statistics class. She randomly selected 9 students. Their average age was 19.1 years with a standard deviation of 1.5 years. 81. What is the best point estimate for the population mean? A) 2.1 years B) 1.5 years C) 19.1 years D) 9 years Answer: C 82. What is the 95% confidence interval for the population mean? A) [0.97, 3.27] B) [15.64, 22.56] C) [17.97, 20.23] D) [17.95, 20.25] Answer: D

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83. What is the 99% confidence interval for the population mean? A) [17.42, 20.78] B) [17.48, 20.72] C) [14.23, 23.98] D) [0.44, 3.80] Answer: A Use the following to answer...

...
QoS Techniques: MPLS
CET 2486C – Network Technologies
Professor:
November 27, 2012
Abstract
MPLS or Multi Protocol Label Switching is a networking technology that functions between layers 2 and 3 of the OSI model. MPLS constitutes of adding a label (sometimes called “Shim” because of their placement between layer 3 and layer 2 headers.) to the data package, this label contains special addressing and sometimes prioritization information. Because the MPLS label...

...is differing from sample to sample and follow the same trend as mean.
Introduction of the test:
By analyzing the new samples, the client would be able to know that, whether the process was operating satisfactorily or not. If the process was not operating satisfactorily, then corrective action would be taken to eliminate the problem. In this case the mean for the process is 12. The hypothesis test suggested by Quality Associates follows:
H0: μ=12
Ha:...

...i Chapter9 Notes
What is Audit Sampling?
* Audit Sampling – applying a procedure to less than 100% of a population to estimate some characteristic of that population
* Sampling Risk – risk that a sample may not be representative of the population
* Risk that the auditor’s conclusion based on the sample may be different from the conclusion they would reach if they examined every item in the population
* Non-sampling Risk – risk...

... Statistics – Case Chapter9
1. It is not proper to multiply the average order size by the number of addresses (1.3 million people = population) in the target mailing because the sample is representative of the 600,000 people in the database, not the 1.3 million target population, thus you cannot use the average of the sample as an estimate for the population. Also, multiplying by 1.3 million would suggest that the entire 1.3 million people would be purchasing....

...CHAPTER EIGHT
INTERVAL ESTIMATION
MULTIPLE CHOICE QUESTIONS
In the following multiple choice questions, circle the correct answer.
1. When s is used to estimate (, the margin of error is computed by using
a. normal distribution
b. t distribution
c. the mean of the sample
d. the mean of the population
Answer: b
2. As the number of degrees of freedom for a t distribution increases, the difference between the t...

...outcome are countable 8. The mean life of pair of shoes is 40 months with a standard deviation of 8 months. If the life of the shoes is normally distributed, how many pairs of shoes out of one million will need replacement before 36 months? 308,500 9. If the sampled population has a mean of 48 and standard deviation 16, then the mean and the standard deviation for the sampling distribution x for n=16 48 and 4 10. The MPG (MILES PER GALLON) for a mid-size car is normally...

...Chapter9 (Group & Teams)
How can we characterize groups?
Roles, norms, status, size, cohesiveness, diversity
To explain special types of team dynamics:
Social loafing, group link, group shift
Individual concepts – Psychological contacts, deviance
A work group is 2 more more people who: Maintain stable patterns of relationships in which they have influence over each other, they share common goals, and perceive themselves as being in a group. Members can identify...

...Chapter9 closing case
Ashford University
BUS 650 Managerial Finance
When should Bunyan Lumber, harvest the forest?
The cash flow will grow at the inflation rate of 3.7%. Utilizing the real cash flow formula
(1+R) =v (1+R)(1+H)
1.10 = (1+R)(1.037)
R= 6.08%
The conservation funds are anticipated to grow slower than the inflation rate. The return for the conservation fund will be,
(1+R) = (1+R) (1+H)
1.10 = (1+R) (1.032)
R= 6.5%
The cash flow from...

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