# Chapter 14 Solutions

Topics: Harshad number, Blade, Invoice Pages: 14 (1676 words) Published: November 13, 2012
Solutions for Review Problems of Chapter 14
1. a. Given the following diagram for a product, determine the quantity of each component required to assemble one unit of the finished product.

b.

Draw a tree diagram for the stapler:

a.

F: 2 J: 2 x 2 = 4 D: 2 x 4 = 8

G: 1 L: 1 x 2 = 2 J: 1 x 2 = 2

H: 1 A: 1 x 4 = 4 D: 1 x 2 = 2

Totals: F = 2; G = 1; H = 1; J = 6; D = 10; L = 2; A = 4 b.

Stapler

Top Assembly

Base Assembly

Cover

Spring

Slide Assembly

Base

Slide

Spring

2.

The following table lists the components needed to assemble an end item, lead times, and quantities on hand.

a. b.

If 20 units of the end item are to be assembled, how many additional units of E are needed? (Hint: You don’t need to develop an MRP plan to determine this.) An order for the end item is scheduled to be shipped at the start of week 11. What is the latest week that the order can be started and still be ready to ship on time? (Hint: You don’t need to develop an MRP plan for this part either.)

a. B: 20 x 2 = 40 – 10 = 30 E: 30 x 2 = 60 – 12 = 48

C: 20 x 1 = 20 – 10 = 10 E: 10 x 2 = 20
End Item

D: 20 x 3 = 60 – 25 = 35 E: 35 x 2 = 70

Total: 48 + 20 + 70 = 138 b.
B(2)

C

D(3)

E(2)

F(3)

G(2)

E(2)

H(4)

E(2)

Total LT 4 5 5 5 6 The longest sequence is 6 weeks. Week 11 – 6 weeks = Week 5.

5

3.

End item P is composed of three subassemblies: K, L, and W. K is assembled using 3 Gs and 4 Hs; L is made of 2 Ms and 2 Ns; and W is made of 3 Zs. On-hand inventories are 20 Ls, 40 Gs, and 200 Hs. Scheduled receipts are 10 Ks at the start of week 3, 30 Ks at the start of week 6, and 200 Ws at the start of week 3. One hundred Ps will be shipped at the start of week 6, and another 100 at the start of week 7. Lead times are two weeks for subassemblies and one week for components G, H, and M. Final assembly of P requires one week. Include an extra 10 percent scrap allowance in each planned order of G. The minimum order size for H is 200 units. Develop each of the following: a. b. c. d. A product structure tree. An assembly time chart. A master schedule for P. A material requirements plan for K, G, and H using lot-for-lot ordering.

Solution: a.

Product Structure Tree

P K 3G
c. Master Schedule d. Weeks Quantity LT = 1 wk. Beg. Inv. 1 2 3 4 5 Beg. Inv. 1 2 3 4 5 6 100 6 100 7 100 7 100

L 4H 2 2N

W 3Z

P

Gross requirements Scheduled receipts Projected on hand Net requirements Planned-order receipts Planned-order releases K LT = 2 wk. Beg. Inv. 1 2 3 4 100 5 100 10 10 10 10 90 90 90 Beg. Inv. 1 2 3 270 40 40 40 40 230 253 253 231 210 231 70 4 210 5

100 100 100 6 100 30 70 70

100 100

7

Gross requirements Scheduled receipts Projected on hand Net requirements Planned-order receipts Planned-order releases G(3) LT = 1 wk.

6

7

Gross requirements Scheduled receipts Projected on hand Net requirements Planned-order receipts Planned-order releases

H(4)

LT = 1 wk.

Beg. Inv.

1

2

3 360

4 280 40 240 240

5

6

7

Gross requirements Scheduled receipts Projected on hand Net requirements Planned-order receipts Planned-order releases 200 200 200 200

200 160 200 240

4.

Oh No!, Inc., sells three models of radar detector units. It buys the three basic models (E, F, and G) from a Japanese manufacturer and adds one, two, or four lights (component D) to further differentiate the models. D is bought from a domestic producer.

Lead times are one week for all items except C, which is two weeks. There are ample supplies of the basic units (E, F, and G) on hand. There are also 10 units of B, 10 units of C, and 25 units of D on hand. Lot-sizing rules are lot-for-lot ordering for all items except D, which must be ordered in multiples of 100 units. There is a scheduled receipt of 100 units of D in week 1. The master schedule calls for 40 units of A to be produced in week 4, 60 units of B in...