1. A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in:  A. 5 days 
  B. 6 days 

 C. 10 days 
  D. 10 1 days
 2 
 

Answer: Option C
Explanation:
(B + C)'s 1 day's work =  1 + 1  = 7 .
  9  12   36 
Work done by B and C in 3 days =  7 x 3  = 7 .   36    12 
Remaining work =  1  7  = 5 .
   12   12 
Now, 1 work is done by A in 1 day.
 24 
So, 5 work is done by A in  24 x 5  = 10 days.  12    12  
1. . The square root of 64009 is:
 A. 253 
  B. 347 

 C. 363 
  D. 803 

Answer: Option A
Explanation:
264009( 253
4

45240
225

503 1509
 1509

 X

* 64009 = 253.
* 3.
How many marks did Tarun secure in English? 
I.  The average mark obtained by Tarun in four subjects including English is 60.  II.  The total marks obtained by him in English and Mathematics together are 170.  III.  The total marks obtained by him in Mathematics and Science together are 180.  *
 A. I and II only 
  B. II and III only 

 C. I and III only 
  D. All I, II and III 

 E. None of these 
   
* Answer: Option E
* Explanation:
* I gives, total marks in 4 subjects = (60 x 4) = 240.
* II gives, E + M = 170
* III gives, M + S = 180.
* Thus, none of (A), (B), (C), (D) is true.
* Correct answer is (E).
The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is:  A. 40% 
  B. 42% 

 C. 44% 
  D. 46% 

Answer: Option CExplanation:Let original length = x metres and original breadth = y metres.Original area = (xy) m2. New length =  120 x m =  6 x m.   100     5  
New breadth =  120 y m =  6 y m.
  100     5  
New Area =  6 x x 6 y m2 =  36 xy m2.   5  5     25  
The difference between the original area = xy and newarea 36/25 xy is= (36/25)xy  xy= xy(36/25  1) = xy(11/25) or (11/25)xy Increase % =  11 xy x 1 x 100 % = 44%.   25  xy   
Learn more problems on : Area Discuss about this problem : Discuss in Forum 
5. Robert is travelling on his cycle and has calculated to reach point A at 2 P.M. if he travels at 10 kmph, he will reach there at 12 noon if he travels at 15 kmph. At what speed must he travel to reach A at 1 P.M.?    A. 8 kmph 
  B. 11 kmph 

 C. 12 kmph 
  D. 14 kmph 

Answer: Option CExplanation:Let the distance travelled by x km. Then, x  x = 2  10  15 
3x  2x = 60x = 60 km. Time taken to travel 60 km at 10 km/hr =  60 hrs = 6 hrs.   10  
So, Robert started 6 hours before 2 P.M. i.e., at 8 A.M. Required speed =  60 kmph. = 12 kmph.   5  
Learn more problems on : Time and Distance Discuss about this problem : Discuss in Forum 
Direction (for Q.No. 6):Find out the wrong number in the given sequence of numbers. 6. 8, 13, 21, 32, 47, 63, 83 
  A. 47 
  B. 63 

 C. 32 
  D. 83 

Answer: Option AExplanation:Go on adding 5, 8, 11, 14, 17, 20.So, the number 47 is wrong...
Share this Document
Let your classmates know about this document and more at StudyMode.com