Angular momentum and its properties were devised over time by many of the great minds in physics. Newton and Kepler were probably the two biggest factors in the evolution of angular momentum. Angular momentum is the force which a moving body, following a curved path, has because of its mass and motion. Angular momentum is possessed by rotating objects. Understanding torque is the first step to understanding angular momentum.Torque is the angular "version" of force. The units for torque are in Newtonmeters. Torque is observed when a force is exerted on a rigid object pivoted about an axis and. This results in the object rotating around that axis. "The torque ? due to a force F about an origin is an inertial frame defined to be ? ? r x F"1 where r is the vector position of the affected object and F is the force applied to the object.To understand angular momentum easier it is wise to compare it to the less complex linear momentum because they are similar in many ways. "Linear momentum is the product of an object's mass and its instantaneous velocity. The angular momentum of a rotating object is given by the product of its angular velocity and its moment of inertia. Just as a moving object's inertial mass is a measure of its resistance to linear acceleration, a rotating object's moment of inertia is a measure of its resistance to angular acceleration."2 Factors which effect a rotating object's moment of inertia are its mass and on the distribution of the objects mass about the axis of rotation. A small object with a mass concentrated very close to its axis of rotation will have a small moment of inertia and it will be fairly easy to spin it with a certain angular velocity. However if an object of equal mass, with its mass more spread out from the axis of rotation, will have a greater moment of inertia and will be harder to accelerate to the same angular velocity.3To calculate the moment of inertia of an object one can imagine that the object...
...Cannot tell.
If m1 * L2 = m2 * L1, is there a negative torque?
Given particular values of L1, L2, and m1, is it always possible to choose m2 such that the masses have no angular acceleration?
For m1 = m2, does the angular acceleration depend only on L1 / L2 ? (If it depends on the actual values of L1 and L2, put 'no'.)
If m1 = m2, will the masses have an angular acceleration?
Problem Weight is: 1  Tries 0/6  
If L1 = 0.490 m, L2 = 1.18m, m1 = 4.10 kg, and m2 = 3.40 kg, what is the angular acceleration of the beam?
Problem Weight is: 1  Tries 0/6  

Problem 4 
A 1.42 kg particle moves in the xy plane with a velocity of v = (4.26i  3.43j) m/s. Determine the particle's angularmomentum when its position vector is r = (1.49i + 2.36j) m. Enter the kcomponent of the angularmomentum with correct units.
Problem Weight is: 1  Tries 0/6  

Problem 5 
On a frictionless table, a glob of clay of mass 0.760 kg strikes a bar of mass 0.740 kg perpendicularly at a point 0.290 m from the center of the bar and sticks to it.
a) If the bar is 1.460 m long and the clay is moving at 5.400 m/s before striking the bar, what is the final speed of the center of mass?
Problem Weight is: 1  Tries 0/6  
b) At what angular speed does the bar/clay system rotate about its...
...Radial Distance
(m)
Tangential Velocity
(m/s)
AngularMomentum (kg m2/s)
(in red above the rotating ball)
1.85
5.14
2.38
1.40
6.79
2.38
1.00
9.50
2.38
0.80
11.88
2.38
0.60
15.83
2.38
0.40
23.75
2.38
Questions:
1. Using the data you have gathered and your knowledge of the law of conservation of angularmomentum, explain the results for the angularmomentum data column.
 Theangularmomentum of a rigid object is defined as the product of the moment of inertia and the angular velocity. All parts of the isolated system were held constant. Since there was no external torque on the object, the angularmomentum could not have changed.
2. Find line or curve of best fit. What is the constant for this graph? Refer to lesson 1.13 for tips.
 The constant is 9.5036.
3. Using your knowledge of graphs, describe the relationship between radial distance and tangential velocity.
 Radial distance and tangential velocity have an inverse relationship. As radial distance increases, tangential velocity decreases.
4. Visit the following site: Conservation of AngularMomentum Demonstration. Play the video. Explain the changes in the woman’s speed as she moves her arms.
 While her arms are pulled in, there is a small moment of inertia. This is because only a small amount of torque needed to move...
...inappropriate help. I understand that any evidence which contradicts the foregoing statement may be used against me, and I am prepared for the ensuing consequences thereof.” 3. Maximum of 2 problems per sheet. Show all relevant solutions neatly and state any assumptions used in solving. Box all final answers.
PROBLEM NO.1 In the crank piston system shown, a piston P is connected to a crank AB (b 16 cm.) by a 2 kg slender rod B ( l 40 cm.). The mass of the crank AB can be considered to be very small. During a test of the system, crank AB is made to rotate with a constant angular velocity of 60 rad/s clockwise. There is no force applied to the face of the piston. When 60the distance between points D and A , d, is 43.081 cm and the angle of connecting rod BD from the horizontal is 30o. Consider this instant when 60, answer the following questions:
d
1.A) Show by kinematic analysis that the angular acceleration of connecting rod BD is 1328.5 rad/s2 1.B) Show by kinematic analysis that the acceleration of the mass center G of connecting rod BD has the horizontal and vertical components of acceleration aGx = 188.60 m/s2 and aGy = 249.42 m/s2; respectively. 1.C) Draw clearly the FBD = EFD diagram for the connecting rod BD. Label all points and vectors properly. 1.D) Determine the force acting at point B. 1.E) Determine both the horizontal and vertical components of the force acting on the bar BD at hinge D. PROBLEM NO.2...
...laws and principals of mechanics about human performance in order to gain greater indepth understanding and knowledge about specific details. It is important to have wide understanding of the applications of physics into sport, as physical principles such as motion, resistance, momentum and friction play a part in most sports. Learning about the biomechanics behind a volleyball overhand serve and why we need force, acceleration, gravity, levers and power to produce the most optimum serve. The biomechanics principles are force and motion, momentum, leverage and fluid mechanics.
(http://codysbiomechanisvolleyballblog.blogspot.com.au/)
Force and motion. This principal is found mostly in the sprinting and jumping portions of the serve! When the player sprints, they exert a force against the ground in an angle.
The momentum from the sprint is then transfered to the momentum of the jump (So a fast sprint will result in a high jump) Once a contact is made with the ball, the momentum of the jump is transferred
to the ball. This increases the velocity of the ball, making it go over the net and far into the opposing court! Momentum is being gained through sprint. Momentum is transferred to jump then Momentum is transferred to the ball This principal also plays a vital role when the player lands from their serve. The players must bend their legs such that they will be...
...difference in momentum? What is their difference in kinetic energy?
2. A 12 g bullet is fired horizontally into a 96 g wooden block initially at rest on a horizontal surface. After impact, the block slides 7.5 m before coming to rest. If the coefficient of kinetic friction between block and surface is 0.60, what was the speed of the bullet immediately before impact?
3. A ball bounces upward from the ground with a speed of 14 m/s and hits a wall with a speed of 12 m/s. How high above the ground does the ball hit the wall? Ignore air resistance.
4. A 200 g mass is attached to a spring of spring constant k. The spring is compressed 15 cm from its equilibrium value. When released the mass reaches a speed of 5 m/s. What is the spring constant (in N/m)?
5. A 34g bullet traveling at 120m/s embeds itself in a wooden block on a smooth surface. The block then slides toward a spring and collides with it. The block compresses the spring (k=100 N/m) a maximum of 1.25 cm. Calculate the mass of the block of wood.
6. If a force of 300N is exerted upon a 60 kg mass for 3 seconds, how much impulse does the mass experience?
7. An 80kg man and his car are suddenly accelerated from rest to a speed of 5 m/s as a result of a rearend collision. Assuming the time taken to be 0.3s, find:
a) the impulse on the man and
b) the average force exerted on him by the back seat of his car.
8. An airplane propeller is rotating at 1900 rev/min.
a. Compute the...
...CONSERVATION OF MOMENTUM PRACTICAL WRITE UP
AIM: To investigate if momentum is conserved in twodimensional interactions within an isolated system.
HYPOTHESIS: Without the effects of friction the momentum will be conserved in the isolated system. In all three experiments the momentum before the interaction will equal the momentum after the interaction.
METHOD: An air hockey table was set up and a video camera on a tripod was placed over the air hockey table. The camera was positioned so it was directly above the air hockey table facing downwards. The air hockey table was turned on and two near identical pucks were placed on the table, one at one end of the table and one in the centre. The puck at the end of the table was launched by hand towards the other puck which was stationary. On impact the first puck continued in motion and initiated the motion of the second puck. The collision was filmed on the video camera. After this a second experiment was set up with the same two pucks, but this time they were placed in either corner of the air hockey table. They were launched at the same time into the centre of the table, where they collided and bounced off each other and this collision was also filmed. In the final experiment the two pucks were replaced with larger pucks with Velcro around the edges. Like the previous experiment the two pucks were placed in two of the corners of the table and launched at...
...Angular Kinematics
An object on a point that rotate a fixed axis has circular motion around the same axis. Linear quantities cannot be used for circular motion. This is due to the extended objects rotational motion rather that a particles linear motion. Circular motion, for this reason, is described in terms of the change in angular position. Except for the points on the axis, all the points on a rotating rigid object during any time interval move through the same angle.
Many equations describing circular motion require angles to be measured in radians (rad) instead of degrees. Any angle θ measured in radians, in general, is defined by the equation. If the arc length, s, and the length of the radius, r, is equal, the angle θ swept by r is equal to one radian. The units cancel and the abbreviation radian is substituted because θ is the ratio of the length of the radius (distance) to an arc length (also a distance). In other words, the radian is a pure number, with no dimensions.
When the light on a Ferris wheel moves one revolution of the wheel (angle of 360˚) the circumference of a circle, which is r, is equal to the arc length s. By substituting this value for s (into the equation above) gives the corresponding angle in radians . Hence radians equals 360˚, or one complete revolution. An angle approximately 2(3.14) =6.28 radians corresponds with one revolution. Figure 1 to the right is a circle that is marked with both degrees and radians....
...Collision and Conservation of Momentum
Collision, a normal phenomenon in our daily life, also is familiar by people in physics field. As we can imagine, there are many interesting among collision cause our attention to think about what is this exactly about and how does is work or maybe why is that such as there maybe some neutron stars intensely hurtling in outer space or two small eggs hitting each other. Outer space is filled with infinite particles that maybe as small as things people cant find out or measure so far and collisions are mostly about those small particles moving and hitting. For example, light wouldn’t be so bright according to its mass and the reason that it delivers light is because collision  namely fraction – to produce photon and then integrate light. A collision is an isolated event in which two o more moving bodies exert forces on each other for a relatively short time. Even though, many people would refer collision to accidents where there are object badly crashed, what my topic will be focused on are those phenomenon among physics world. Moreover, when scientists use the word of “collision”, they try to imply nothing about the magnitude of the forces. Collision was ever a hot topic drawing many physicists’ attention. After plenty of delving, physicists establish the momentum conservation law. Collision is a typical characteristic in microcosm in physics. Fortunately, collision can be simply solved from difficultly...