Statistics Final Review Chapters 7,8,9

Pages: 9 (1272 words) Published: April 22, 2012
1.
STAT10T 7.2.1-2
(Points: 5.0)     Solve the problem.

Find the critical value zα/2 that corresponds to a degree of confidence of 91%.

a. 1.645

b. 1.75

c. 1.34

d. 1.70
2.
STAT10T 7.2.3-2
(Points: 5.0)     Solve the problem.

The following confidence interval is obtained for a population proportion, p: 0.817 < p < 0.855
Use these confidence interval limits to find the point estimate, .

a. 0.833

b. 0.817

c. 0.839

d. 0.836

3.
STAT10T 7.2.4-3
(Points: 5.0)     Find the margin of error for the 95% confidence interval used to estimate the population proportion.

In a survey of 7100 T.V. viewers, 40% said they watch network news programs.

a. 0.0131

b. 0.0150

c. 0.0114

d. 0.00855
4.
STAT10T 7.2.5-1
(Points: 5.0)     Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p.

n = 61, x = 19; 95 percent

a. 0.194 < p < 0.428

b. 0.195 < p < 0.427

c. 0.213 < p < 0.409

d. 0.214 < p < 0.408
5.
STAT10T 7.2.6-2
(Points: 5.0)     Find the minimum sample size you should use to assure that your estimate of will be within the required margin of error around the population p.

Margin of error: 0.016; confidence level: 97%; and unknown

a. 34

b. 4599

c. 1

d. 4598
6.
STAT10T 7.2.7-5
(Points: 5.0)     Find the minimum sample size you should use to assure that your estimate of will be within the required margin of error around the population p.

Margin of error: 0.008; confidence level: 99%; from a prior study, is estimated by 0.164

a. 14,205

b. 114

c. 8230

d. 12,785
7.
STAT10T 7.2.9-1
(Points: 5.0)     Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p.

A survey of 865 voters in one state reveals that 408 favor approval of an issue before the legislature. Construct the 95% confidence interval for the true proportion of all voters in the state who favor approval.

a. 0.438 < p < 0.505

b. 0.435 < p < 0.508

c. 0.444 < p < 0.500

d. 0.471 < p < 0.472
8.
STAT10T 7.3.4-1
(Points: 5.0)     Use the confidence level and sample data to find a confidence interval for estimating the population μ.

Test scores: n = 98, = 81.9, σ = 7.8; 99 percent

a. 80.6 < μ < 83.2

b. 80.4 < μ < 83.4

c. 79.9 < μ < 83.9

d. 80.1 < μ < 83.7
9.
STAT10T 8.2.3-2
(Points: 5.0)     Assume that the data has a normal distribution and the number of observations is greater than fifty. Find the critical z value used to test a null hypothesis.

α = 0.09 for a right-tailed test.

a. ±1.96

b. +1.96

c. +1.34

d. ±1.34
10.
STAT10T 8.2.4-2
(Points: 5.0)     Find the value of the test statistic z using z = .

The claim is that the proportion of drowning deaths of children attributable to beaches is more than 0.25, and the sample statistics include drowning deaths of children with 30% of them attributable to beaches.

a. 2.86

b. 2.71

c. -2.86

d. -2.71
11.
STAT10T 8.2.5-3
(Points: 5.0)     Use the given information to find the P-value.

The test statistic in a left-tailed test is z = -1.83.

a. 0.0336

b. 0.4326

c. 0.0443

d. 0.4232
12.
STAT10T 8.3.2-2
(Points: 5.0)     Find the P-value for the indicated hypothesis test.

In a sample of 88 children selected randomly from one town, it is found that 8 of them suffer from asthma. Find the P-value for a test of the claim that the proportion of all children in the town who suffer from asthma is equal to 11%.

a. 0.5686

b. 0.2843

c. 0.2157

d. -0.2843
13.
STAT10T 9.4.1-1
(Points: 5.0)     The two data sets are dependent. Find to the nearest tenth.

a. 32.0

b. 19.2

c. 40.0

d. 41.6
14.
STAT10T 9.4.3-1
(Points: 5.0)     Assume that you want to test the claim that the paired sample data come from a population for which the mean difference is μd =...

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