1. Measuring the Length
* 1m = 1000cm = 1x102cm
* 1m= 1000mm = 1x103mm
* 1cm = 10mm = 1x101mm
2. Measuring the Volume
* 1L = 10dL = 1x101dL
* 1L = 1000mL = 1x103mL
* 1dL = 100mL = 1x102mL
* 1mL = 1cm = 1cc These are all the same (Notations)
3. Measuring the Mass
* 1Kg = 1000g = 1x103g
* 1g = 1000mg = 1x103mg
* 1mg = 1000µg = 1x103µg
Writing the Conversion factors
To convert you will have to put one in the Numerator and Denominator Example.
1hr = 60min
60min1hr or 1hr60min
60min per 1hr or 1hr per 60min
Example.
1lb = 454g
454g1lb or 1lb454g
Example.
1 tablet = 500mg of vitamin C
500mg of vitamin C/ 1 tablet
1 tablet/ 500mg of vitamin C
Example.
164lb kg = ?
Given unit (x) one or more conversion factors = Needed Unit (will always be in the numerator) 164lb x 1kg2.20lb =
164 (x) 1kg2.20 =
74.5454kg (74.5kg)
...Common Prefixes
Prefix  Meaning  Example 
a, an  without  amoral 
ante  before  antecedent 
anti  against  anticlimax 
auto  self  autopilot 
circum  around  circumvent 
co  with  copilot 
com, con  with  companion, contact 
contra  against  contradict 
de  off, away from  devalue 
dis  not  disappear 
en  put into  enclose 
ex  out of, former  extract, expresident 
extra  beyond, more than  extracurricular 
hetero  different  heterosexual 
homo  same  homonym 
hyper  over, more  hyperactive 
il, im, in, ir  not, without  illegal, immoral, inconsiderate, irresponsible 
in  into  insert 
inter  between  intersect 
intra  between  intravenous 
macro  large  macroeconomics 
micro  small  microscope 
mono  one  monocle 
non  not, without  nonentity 
omni  all, every  omniscient 
post  after  postmortem 
pre, pro  before, forward  precede, project 
sub  under  submarine 
syn  same time  synchronize 
trans  across  transmit 
tri  three  tricycle 
un  not  unfinished 
uni  one  unicorn 

 
A suffix is a letter or a group of letters attached to the end of a word to form a new word or to alter the grammatical function of the original word. For example, the verb read can be made into the noun reader by adding the suffix er; read can be made into the...
...1. Which equation below represents the quadratic formula?
*a. b±b24ac2a = x
b. a2+b2=c2
c. fx=a0+n=1∞ancosnπxL+bnsinnπxL
2. Which of the following represents a set of parallel lines?
a. Option one
b. Option two
*c. Option three
3. What is the definition of an obtuse angle?
*a. an angle greater than 90°
b. an angle equal to 90°
c. an angle less than 90°
4. Which formula below represents the area of a circle?
a. A=2πr
*b. A=πr2
c. A=π2r
d. A= √π
5.
What geometric term is represented by the image below?
a. a corner
*b. a crosssection
c. the circumference
d. the perimeter
11. Using the data in the table below, calculate the mean, or average, number of points scored by Player B.
 Game 1  Game 2  Game 3  Game 4  Game 5 
Player A  13  12  9  11  13 
Player B  12  11  15  20  12 
*a. 14
b. 11.5
c. 13
d. 13.67
6. This instrument is commonly used by surveyors. It measures horizontal and vertical angles to determine the location of a point from other known points at either end of a fixed baseline, rather than measuring distances to the point directly. What is it called?
a. triangulator
b. binocular
c. tripod
*d. theodolite
7. What is the name of the missing shape in the flowchart below?
a. Acute
b. Obtuse
*c. Isosceles
d. Right
8. What category includes all of the items on the list below?
* Square
* Rectangle
*...
...determine the bulk velocity of the stream using Equation 1.
(Eqn. 1)
Where is the flowrate in m3/s and A is the crosssectional area of the pipe. To find the flowrate, we multiply the flowmeter reading by the constant
and convert from gallons to cubic meters as follows:
The cross sectional area of the 7.75mm pipe is
Plugging these values into Equation 1, we obtain a bulk velocity .
With the bulk velocity value, we can find the Reynolds number of the flow using Equation 2.
(Eqn. 2)
Plugging in known values to Equation 2, we find:
The experimental friction factor of the pipe can be calculated as:
(Eqn. 3)
Using the pressure drop for the chosen sample from smallest smooth copper pipe across the known distance L, we obtain an experimental friction factor
The theoretical friction factor for smooth pipes can be calculated with the Petukhov formula:
(Petukhov Formula)
Using this formula with our calculated Reynolds number yields a theoretical friction factor of
Because Pipe 4 is a rough pipe, this Petukhov Formula does not apply and we must perform additional sample calculations. From the first data point for the fourth pipe we obtain the following flow properties:
Using Equations 2 and 3 we can find the following Reynolds number and experimental friction factor:
The theoretical friction factor for a rough pipe can be found by calculating the parallel...
...Calorimetry Equations
Monday, October 28, 2013
12:00 PM
TOOL BOX
q=mc∆T
Water sp. Heat
Calorimetry : the measurement of energy (calorie)
Calorimeter : tool used to measure energy by Measuring the change in temperature
Equation :
q=mc∆T
What is the difference between Calorimetry and Calorimeter?
Quantity of
Energy (Cal.)
Mass
(g)
Specific heat (given) (Cal/g)
Change in temperature (℃ )
(Endshort)
What is the dance that we learned in class today about our new equation?
Name all the Specific heat type and what they vary? ( if that makes sense)
Specific heat
• Unique to every substance
• Amount of energy required to increase 1g of substance by 1℃
High specific heat
• Needs large amount of energy to change temp ex. Water
Low specific heat
• Changes temp. easily ex.metal
Summary:
In today's class we talked a about the equation(s) of calorimetry. Calorimetry is the measurement of energy , and Calorimeter Is a tool used to measure energy by measuring the change in temperature. We also learn about the Specific heat, high specific heat, and low specific heat. But the main thing is that the new equation we learn today is
q=mc∆T
.Calorimetry
Sunday, October 27, 2013
6:35 PM
Calorie : Unit of energy Metry : Measurement
Calorimetry :
• Measurement of energy
Energy : The ability to do work...
...There are now two separate equations: 60 = 6b  6c and 60 = 3b + 3c
Solve both equations for b: b = 10 + c b = 10  c
Now make both equations equal each other and solve for c: 10 + c = 10  c 2c = 0 c = 0
The speed of the current was 0 mph Now, plug the numbers into one of either the original equations to find the speed of the boat in still water.
I chose the first equation: b = 10 + c or b = 10 + 0 b = 10
The speed of the boat in still water must remain a consistent 10 mph or more in order for Wayne and his daughter to make it home in time or dinner.
My Solution: c = current of river b = rate of boat d = s(t) will represent (distance = speed X time) Upstream: 60 = 6(bc)
Downstream: 60 = 3(b+c)
There are now two separate equations: 60 = 6b  6c and 60 = 3b + 3c
Solve both equations for b: b = 10 + c b = 10  c
Now make both equations equal each other and solve for c: 10 + c = 10  c 2c = 0 c = 0
The speed of the current was 0 mph Now, plug the numbers into one of either the original equations to find the speed of the boat in still water.
I chose the first equation: b = 10 + c or b = 10 + 0 b = 10
The speed of the boat in still water must remain a consistent 10 mph or more in order for Wayne and his daughter to make it home in time or dinner.
My Solution: c = current of river b = rate of boat d = s(t) will...
...
The short story Cold Equations by Tom Godwin takes place on a ship called EDS. The space cruiser is piloted by a man named Barton. He has an order of killing the stowaway who snuck onto the ship because the weight on the EDS is too much for the ship to handle. In the process of hunting down the stowaway, he realizes it was a young innocent girl named Marilyn. Once Barton understands what kind of person Marilyn is, he doesn’t kill her immediately because he knows her reasons were pure. Marilyn only wanted to see her brother, Gerry, again after ten years of being apart and was ignorant to the fact that her life can end with the decision of sneaking onto the ship. Barton begins to feel compassion after being with her and tries to comfort her, but knows what her fate is. He lets Marilyn live long enough to let her speak with Gerry once more before he follows through with the command. After Gerry and Marilyn speak he ejects her out into space. The ending was logical and no other endings would be possible because one the equation that was calibrated delicately, and two Barton could not throw the out the fever serums because that is the main reason for going on the trip to Woden.
A theoretical ending of Cold Equations could have been that Barton sacrifices himself for Marilyn, but since she is lighter than him, the fragile calibrated equation would be disrupted due to the change in weight. On EDS everything on ship is...
...CHAPTER 2
FIRST ORDER DIFFERENTIAL EQUATIONS
2.1 Separable Variables
2.2 Exact Equations
2.2.1 Equations Reducible to Exact Form.
2.3 Linear Equations
4. Solutions by Substitutions
2.4.1 Homogenous Equations
2.4.2 Bernoulli’s Equation
2.5 Exercises
In this chapter we describe procedures for solving 4 types of differential equations of first order, namely, the class of differential equations of first order where variables x and y can be separated, the class of exact equations (equation (2.3) is to be satisfied by the coefficients of dx and dy, the class of linear differential equations having a standard form (2.7) and the class of those differential equations of first order which can be reduced to separable differential equations or standard linear form by appropriate.
2.1 Separable Variables
Definition 2.1: A first order differential equation of the form
[pic]
is called separable or to have separable variables.
Method or Procedure for solving separable differential equations
(i) If h(y) = 1, then
[pic]
or dy = g(x) dx
Integrating both sides we get
[pic]
or [pic]
where c is the constant of integral
We can write
[pic]
where G(x) is an antiderivative...
...percentage of an element in a compound you can use the following equation:
% Mass = Ar x the number of atoms (of that element) x 100
Mr (of the whole compound)
E.g. Find the % nitrogen in NH4NO3
% N = (14 X 2) X 100
80
= 35%
Try the following (see Ar values page 3, if any aren’t there look at your periodic table in your homework diary.
1. Find the percentages by mass of
a. nitrogen in nitrogen monoxide NO
b. lithium in lithium oxide Li2O
c. carbon in ethane C2H6
d. magnesium in magnesium nitride Mg3N2
2. State which of these compounds contains the largest percentage by mass of nitrogen:
a. ammonium chloride NH4Cl
b. ammonium nitrate NH4NO3
c. ammonium sulphate (NH4)2SO4
d. ammonia NH3
e. urea CO(NH2)2
3. Give the % by mass of all of the elements in magnesium carbonate MgCO3 .
4. A forensic scientist finds a sample of sodium arsenate, Na2AsO4(s) at the scene of a murder. What is the % composition of arsenic in the compound? Ar As = 75.
Lesson 23
Content Reacting amount calculations
Type of lesson Numeracy
Aim To understand that an equation is a ratio of moles.
To calculate the number of moles of one substance – work out the number of moles of a second substance using the idea of molar ratio/the equation – to work out the mass of the second substance
Syllabus covered ‘calculate the masses of reactants or products, from a balanced symbol equation...