# Ac505 Case Study 2

Pages: 4 (927 words) Published: October 14, 2012
Case Study 2
Springfield Express is a luxury passenger carrier in Texas. All seats are first class, and the following data are available: Number of seats per passenger train car90
Average load factor (percentage of seats filled)70%
Average full passenger fare\$ 160
Average variable cost per passenger\$ 70
Fixed operating cost per month \$ 3,150,000

Formulae’s:
Revenue = Units Sold * Unit price
Contribution Margin = Revenue – All Variable Cost
Contribution Margin Ratio = Contribution Margin ÷ Selling Price Break Even Point in Units = (Total Fixed Costs + Target Profit) ÷ Contribution Margin Break Even Point in Sales = (Total Fixed Costs + Target Profit) ÷ Contribution Margin Ratio Margin of Safety = Revenue - Break Even Points in Sales

Degree of Operating Leverage = Contribution Margin/Net Income Net Income = Revenue – Total Variable Cost – Total Fixed Cost Unit Product Cost using Absorption Cost = (Total Variable Cost + Total Fixed Cost)/# of units

a.What is the break-even point in passengers and revenues per month? Contribution margin = Sales per unit - Variable expenses per unit = \$160 - \$70 = \$90
Break-even point in passengers = Fixed costs ÷ Contribution Margin = 3,150,000 ÷ 90 = 35,000 passengers
Break-even point in revenues per month = Unit sales to break even X Sales per unit = 35,000 X \$160 = \$5,600,000 revenue

b.What is the break-even point in number of passenger train cars per month? Compute number of seats per train car (remember load factor?) = (90 X 70%) = 63
Break-even point in passengers = 35,000 passengers
Number of cars = 35,000 ÷ 63 = 556 cars

c.If Springfield Express raises its average passenger fare to \$ 190, it is estimated that the average load factor will decrease to 60 percent. What will be the monthly break-even point in number of passenger cars? Contribution margin = \$190 – \$70 = \$120

Compute number of seats per train car (remember load factor?) = (90 X 60%) = 54
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